anonymous
  • anonymous
dy/dx = -2sinx + 2cos2x How do I find its critical points?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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myininaya
  • myininaya
set =0
anonymous
  • anonymous
Yes I know this step, its just that I get a cos on one side and a sin on the other side. I don't know how to switch them to the same trig function to solve for x
anonymous
  • anonymous
double angle cos(2x) = 1 - 2sin(x)^2

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anonymous
  • anonymous
ok so the I did the double angle and that gives me: 2sinx = 2(cos^2x - sin^2x) How did you get 1 -2sin(x)^2?
anonymous
  • anonymous
cos(2x) = 1 - 2sin(x)^2 it's a rule you should have 2sinx = 2 - 2sin^2x
anonymous
  • anonymous
it's called the double angle formula
anonymous
  • anonymous
Funny, my book says: Cos2A = cos^2A - sin^2A

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