anonymous
  • anonymous
need help solving this equation in quadratic formula
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
\[4x-4 \over x-2 \]\[= x+6 \over x+5 \] +2
anonymous
  • anonymous
it's supposed to be a fraction but for some reason it didn't work.
amistre64
  • amistre64
a fraction over a fraction right?

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anonymous
  • anonymous
it's 4x-4 over x-2 = x+6 over x+5 (not in fraction form is the +2)
anonymous
  • anonymous
idk why it came up over each other like that. I have the problem presented in a straight line.
amistre64
  • amistre64
\[\frac{4x-4}{x-2} = \frac{x+6}{x+5} ??\]
anonymous
  • anonymous
+2
anonymous
  • anonymous
the 3rd portion of the problem is +2
amistre64
  • amistre64
ok..... the key is to get common denominators straight across.
amistre64
  • amistre64
(4x-4)(x+5) = (x+6)(x-2) + 2(x+5)(x-2)
amistre64
  • amistre64
the common denom fades away to that :)
amistre64
  • amistre64
4xx +16x -20 = xx +4x -12 + 2xx +6x -20
amistre64
  • amistre64
4xx - xx - 2xx = x^2 16x -4x -6x = +6x -20 +12 +20 = +12 x^2 +6x +12 = 0
amistre64
  • amistre64
-6/2 +- sqrt(36 -4(12))/2 looks to be imaginary solutions; or i messed up calculting :)
anonymous
  • anonymous
just to make sure I enter it correctly into the online assignment, does it look like this. only i type the same thing twice, one + one 0\[-6 \over 2 +\sqrt{36-4(12)}\] over 2
anonymous
  • anonymous
wooh, i think that came out different than I anticipated.. SOrry, is there any way you could post it. ha
anonymous
  • anonymous
i one + and one - btw
amistre64
  • amistre64
\[\frac{-6 \pm \sqrt{-12}}{2}\]
anonymous
  • anonymous
okkk thanks!
amistre64
  • amistre64
\[-3 \pm i \sqrt{3}\]
anonymous
  • anonymous
it wont let me type in the square root of 12 negative.. should that become positive?
amistre64
  • amistre64
that should be the simplified form
amistre64
  • amistre64
-3 (+-) i sqrt(3)
anonymous
  • anonymous
ohhh. So the answer isn't a fraction
amistre64
  • amistre64
the answer can be simplified; how it wants you to input it into the program is probably in simplest form; doe sit want "real" roots? or any roots?
anonymous
  • anonymous
it has 2 spots for answers. so both I supose
amistre64
  • amistre64
both isnt an option :) the 2 spots are most likely for the +sqrt and the -sqrt.
anonymous
  • anonymous
yep, they are. ohh, i see what you're asking. it just says to simplify
anonymous
  • anonymous
sorry i'm so confusing :)
amistre64
  • amistre64
lol
anonymous
  • anonymous
Thanks for your help!

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