anonymous
  • anonymous
I have to graph this parabola. (5y^2)+10y-x+4=0 Can somebody show me the steps on how to do this
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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amistre64
  • amistre64
are you sure its entered coorectly?
anonymous
  • anonymous
yes.
amistre64
  • amistre64
then its most likely e geometric equation of a parabola

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dumbcow
  • dumbcow
set it equal to x x = 5y^2 +10y +4 this will give us a sideways parabola
amistre64
  • amistre64
complte the square for the ys
myininaya
  • myininaya
right do you know how to find x and y intercepts?
anonymous
  • anonymous
is it this ( -b/2a , 4ac-b^2/4a) ?
amistre64
  • amistre64
y^2 +2y = x/5 -4/5
dumbcow
  • dumbcow
find vertex using y = -b/2a where a,b,c are the coefficients
amistre64
  • amistre64
(y+1)^2 = x/5 - 4/5 +1
amistre64
  • amistre64
... x/5 + 1/5 =1/5(x+1)
amistre64
  • amistre64
(y+1)^2 = (1/5)(x+1) has the form y^2 = 4ax 1/5 = 4a a = 1/20
amistre64
  • amistre64
the center is at (-1,-1) ang opens to the right
amistre64
  • amistre64
by center I mean vertex ;)

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