A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 5 years ago

I have to graph this parabola. (5y^2)+10y-x+4=0 Can somebody show me the steps on how to do this

  • This Question is Closed
  1. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    are you sure its entered coorectly?

  2. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes.

  3. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    then its most likely e geometric equation of a parabola

  4. dumbcow
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    set it equal to x x = 5y^2 +10y +4 this will give us a sideways parabola

  5. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    complte the square for the ys

  6. myininaya
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    right do you know how to find x and y intercepts?

  7. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    is it this ( -b/2a , 4ac-b^2/4a) ?

  8. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    y^2 +2y = x/5 -4/5

  9. dumbcow
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    find vertex using y = -b/2a where a,b,c are the coefficients

  10. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    (y+1)^2 = x/5 - 4/5 +1

  11. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ... x/5 + 1/5 =1/5(x+1)

  12. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    (y+1)^2 = (1/5)(x+1) has the form y^2 = 4ax 1/5 = 4a a = 1/20

  13. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    the center is at (-1,-1) ang opens to the right

  14. amistre64
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    by center I mean vertex ;)

  15. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.