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anonymous

  • 5 years ago

18 (sigma)(-1)^n2n n=4

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  1. anonymous
    • 5 years ago
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    \[\sum_{n=4}^{18}-1^{n^2n}\] ?? is this the question?

  2. anonymous
    • 5 years ago
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    yes

  3. anonymous
    • 5 years ago
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    actually its( -1^n) 2n

  4. anonymous
    • 5 years ago
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    oh well since it is negative one you know that it will either be 1 or negative 1 for each n in the middle of the paratheses, however since you have a 2n on the outside as an exponent that means that it will always be an even exponent so each time, the answer will be 1. so just go (18 - 4)(1) = 14

  5. anonymous
    • 5 years ago
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    my directions tell me to use a graphing calculator but i have no idea how to put sigma into a calculator?

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