(4)/(x+4)-(7)/(x-2)....i know the answer is (-3)(x+12)/(x+4)(x-2) but what are the steps?

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(4)/(x+4)-(7)/(x-2)....i know the answer is (-3)(x+12)/(x+4)(x-2) but what are the steps?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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just take l.c.m and u wil get the answer
i know the answer i just dont know the steps to get the answer
apply l.c.m rule

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but then we come up with 28 and its not anywhere near the answer
you start w/ different denominators to get a common denominator with binomials multiply them together (x+4)(x-2) For first fraction you added (x-2) so multiply the top by (x-2) 4*(x-2) For 2nd fraction you added (x+4) so multiply top by (x+4) 7*(x+4) this gives 4(x-2) - 7(x+4) all over (x+4)(x-2) distribute on top and add like terms 4x-8-7x-28 =-3x-36 factor out a -3 =-3(x+12) this is still all over (x+4)(x-2) hope that helps
u wil get it by l.c.m , 4(x-2)-7(x+4) whole divided by (x-2)(x+4) (4x-8-7x-28) whole divided by(x-2)(x+4) (-3x-36) whole divided by (x-2)(x+4) u take -3 common from numerator u wil get u r answer

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