## anonymous 5 years ago (22x^5y^3z/16x^3z^5) times (8y^2z^3/11x^3)

1. anonymous

I would simplify what can be simplified and then multiply them together. When multiplying same bases add exponents.

2. anonymous

$22x^5y^3z/ 16x^3z^5 = (22/16)x^2y^3z^{-4}$ and $8y^2z^3/11x^3 = (8/11)y^2z^3x^-3$that multiplied is: $(x^{-1}y^5z^{-1} = y^5/(xz)$ Just add the exponents for each variable, then do the multiplication of the coefficients(which ends up being 1)

3. anonymous

thankss so much!

4. anonymous

$7/(3-\sqrt{2})$

5. anonymous

6. anonymous

.................how do you do it.?

7. anonymous

Rationalize it or what?

8. anonymous

in order to get rid of teh radical in the denominator you have to multiply the top and bottom by the conjugate