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cherrilyn
 5 years ago
∫dx/(x^2+6x+6)^2
Evaluate the integral by completing the square and using trig substitution. After completing the square I got (x+3)^23 but I don't know what to do next
cherrilyn
 5 years ago
∫dx/(x^2+6x+6)^2 Evaluate the integral by completing the square and using trig substitution. After completing the square I got (x+3)^23 but I don't know what to do next

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0your good with the completing the square part: [(x+3)^2 +6+9)]^2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0you are adding +9 inside; so you add +9 outside as well....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0your right there...good job :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lols amistre, "good job" :P

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0you need to substitute the trig..... x^2 1 thing....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0tan = x^2 + 1 sin = 1  x^2 whats the other one? sec?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0don't trig sub needed amistre what is with you and trig subbing!?!?! those are the worst!!! just to regular subbing

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0its in the prob itself...use trig sub lol :) not my fault this time lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0sec^2  1 = tan...i think thats the one...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0err.... (x+3) = sqrt(3)sec(t) 3sec^2(t) 3 = 3(sec^2(t)1) [3tan^2(t)]^2 = 9 tan^4(t)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the integral of (x+3)^23 is \[\frac{1}{3}(x + 3)^3  3x\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oy i should learn to read the question... amistre, i take everything back...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0...but what i did was right...why do you need trig id?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0d(sqrt(3) sec(t))/dt = ....everything? even the ceramic unicorn you gave me for my birthday?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0d(sqrt(3) sec(t))/dt = d(x+3)/dx sqrt(3) sec(t)tan(t) dt = dx [sqrt(3) sec(t)tan(t) dt]/[9 tan^4(t)] is this looking right ;)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{} \frac{\sqrt{3} \sec(t) \tan(t)}{9 \tan^4 (t)}dt\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0we can ignore for the moment the sqrt(3)/9 reduce to: sec(t)/tan^3(t) = sin(t)/cos^4(t)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0you sure you posted the question right?

cherrilyn
 5 years ago
Best ResponseYou've already chosen the best response.0yeah I just don't know how to add the division bar . lol . "Evaluate the integral by completing the square and using trigonometric substitution"

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0frac{top}{bottom} in the editor :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0any ideas how to integrate: sin(t)  ?? cos^4

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0sin(t) = sqrt(1cos^2) sqrt(1cos^2)  doesnt seem to make it easier cos^4

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0cos^2 = 1sin^2 (1sin^2)(1sin^2) = sin^4 2sin^2 +1...... hmmm

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0D(tan^4) = 4 tan^3 sec^2....dont see that helping lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i couldnt get to a result.....at leaast not without pencil and paper to do it with.... and a lot more braincells :)
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