anonymous
  • anonymous
What is the domain of sqrt x^2+2x-24/x^2-9
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[\sqrt{x^+2x-24/x^2-9}\]
anonymous
  • anonymous
You want to find the numbers/intervals for which the function is valid. For rationals you cannot have zero in the denominator and for square root functions, you can not have a negative number.
anonymous
  • anonymous
So infinity to infinity?

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anonymous
  • anonymous
Not quite. You need to solve \[x^2-9\neq0\] for x. And then \[\sqrt{(x^2+2x-24)/(x^2-9)}\ge0\] for x.
anonymous
  • anonymous
x=3 for the first one and x= -6 x= -4/ x= -3 x=3
anonymous
  • anonymous
So the domain is \[x \neq \pm3 and -6\ge x \ge 4\]

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