anonymous
  • anonymous
(I know its another log question, im obviously not very good at these ha) evaluate the expression: log8(subscript)64^7.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[\log_ab^c = c\log_ab \] and \[log_xx^2 = 2 \]
anonymous
  • anonymous
ans is 1/14
anonymous
  • anonymous
how to write these mathematical expressions

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anonymous
  • anonymous
By clicking equation (fun fact: it's not 1/14)
anonymous
  • anonymous
so would it be 7log8? since 64/8 is 8?
anonymous
  • anonymous
logx(subscript) \[x ^{m}\] then answer is 1/m sorry guys i'm not good at typing mathematical equations
anonymous
  • anonymous
and i'm sure it ans is 1/14
anonymous
  • anonymous
\[\log_864^7 \not= \frac{1}{14} \]
anonymous
  • anonymous
was i correct? possibly? maybe? ha
anonymous
  • anonymous
if m is the power to subscript then it comes as 1/m before log
anonymous
  • anonymous
hey inewton \[(64)^{7}\] is subscript
anonymous
  • anonymous
No it isn't, because that makes no sense.
anonymous
  • anonymous
the 8 is the subscript
anonymous
  • anonymous
the 64 is the base, and the 7 is the superscript
anonymous
  • anonymous
ans is 1/14. question is \[\log_{64^{7}} \]8
anonymous
  • anonymous
i mean log8 (subcript)\[64^{7}\]
anonymous
  • anonymous
the question is \[\log_864^7 = 7\log_864 \]
anonymous
  • anonymous
ok, thank you very much
anonymous
  • anonymous
But log_8 64 simplifies further
anonymous
  • anonymous
it simplifies to just 8, right?
anonymous
  • anonymous
No \[\log_ab = c \iff a^c = b\] So log_8 64 = 2 because 8^2 = 64
anonymous
  • anonymous
ohhh, ok. thank you! sorry it took so long!
anonymous
  • anonymous
You're welcome

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