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anonymous

  • 5 years ago

(I know its another log question, im obviously not very good at these ha) evaluate the expression: log8(subscript)64^7.

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  1. anonymous
    • 5 years ago
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    \[\log_ab^c = c\log_ab \] and \[log_xx^2 = 2 \]

  2. anonymous
    • 5 years ago
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    ans is 1/14

  3. anonymous
    • 5 years ago
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    how to write these mathematical expressions

  4. anonymous
    • 5 years ago
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    By clicking equation (fun fact: it's not 1/14)

  5. anonymous
    • 5 years ago
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    so would it be 7log8? since 64/8 is 8?

  6. anonymous
    • 5 years ago
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    logx(subscript) \[x ^{m}\] then answer is 1/m sorry guys i'm not good at typing mathematical equations

  7. anonymous
    • 5 years ago
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    and i'm sure it ans is 1/14

  8. anonymous
    • 5 years ago
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    \[\log_864^7 \not= \frac{1}{14} \]

  9. anonymous
    • 5 years ago
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    was i correct? possibly? maybe? ha

  10. anonymous
    • 5 years ago
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    if m is the power to subscript then it comes as 1/m before log

  11. anonymous
    • 5 years ago
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    hey inewton \[(64)^{7}\] is subscript

  12. anonymous
    • 5 years ago
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    No it isn't, because that makes no sense.

  13. anonymous
    • 5 years ago
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    the 8 is the subscript

  14. anonymous
    • 5 years ago
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    the 64 is the base, and the 7 is the superscript

  15. anonymous
    • 5 years ago
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    ans is 1/14. question is \[\log_{64^{7}} \]8

  16. anonymous
    • 5 years ago
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    i mean log8 (subcript)\[64^{7}\]

  17. anonymous
    • 5 years ago
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    the question is \[\log_864^7 = 7\log_864 \]

  18. anonymous
    • 5 years ago
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    ok, thank you very much

  19. anonymous
    • 5 years ago
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    But log_8 64 simplifies further

  20. anonymous
    • 5 years ago
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    it simplifies to just 8, right?

  21. anonymous
    • 5 years ago
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    No \[\log_ab = c \iff a^c = b\] So log_8 64 = 2 because 8^2 = 64

  22. anonymous
    • 5 years ago
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    ohhh, ok. thank you! sorry it took so long!

  23. anonymous
    • 5 years ago
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    You're welcome

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