A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
I don't understand the underlined step
anonymous
 5 years ago
I don't understand the underlined step

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Please open the attachment for details

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0We are given that (a+b) = (c+d). If that is true, then (a+b)^2 must equal (c+d)^2. But that means that \(a + 2\sqrt{ab} + b = c + 2\sqrt{cd} + d\) And since a+b = c+d we can subtract those terms from both side to get that \[\sqrt{ab} = \sqrt{cd}\] Now we look at: \[(\sqrt{a}\sqrt{b})^2 = a 2\sqrt{ab} + b\] \[(\sqrt{c}\sqrt{d})^2 = c 2\sqrt{cd} + d\] But here again, a+b = c+d, and \(\sqrt{ab} = \sqrt{cd}\) So we can see that the two equations are equal and therefore \[(\sqrt{a}\sqrt{b})^2 =(\sqrt{c}\sqrt{d})^2\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ack, sorry I missed something in the first step.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0We are given that \(\sqrt{a} + \sqrt{b} = \sqrt{c} + \sqrt{d}\)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.