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anonymous
 5 years ago
completing the square to graph the parabola y=2x^28x4
I got stuck but here is what I have
20+y=2(x4)^2
anonymous
 5 years ago
completing the square to graph the parabola y=2x^28x4 I got stuck but here is what I have 20+y=2(x4)^2

This Question is Closed

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0y+4 = 2x^2 8x ; divide everything by 2 y2 = x^2 +4x ; complete the square.. (4/2)^2..+4 to each side y2+4 = x^2 +4x +4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That's perfect. This is telling you that it's a translation in y down 20 units, and to the right in x 4 units.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0y+2 = (x+2)^2 1(y+2) = (x+2)^2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0forgot to divde y by 2 :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0let me show you part of how my teacher showed me how to work it

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(y/2) +2 = (x+2)^2 ; factor the 1/2 from the y (1/2)(y4) = (x+2)^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Actually though, your answer isn't right Marie.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It's in the right form though

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the vertex is at (2,4) and it opens downward....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y+4=2x^28x take the 8/2= 4 then square it which is 16 add 16 to both sides y+20=2x^28x+16 now I take the right side and put it in paranthesis be fore it was added togather 20+y=2(x4)^2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the usual look to this is: y = 2(x+2)^2 +4

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0you cant complete the square when the first term constant is not = 1

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0divide everything by 2 first

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[y = 2x^2 8x 4\] \[y = 2(x^2 + 4x + 2) \] \[y = 2(x^2 + 4x + 2 + (2  2))\] ^ Completing the square \[y = 2(x^2 + 4x + 4 2)\] \[y = 2(x+2)^2 +4\] \[y 4 =2(x+2)^2\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Whoops, sorry. Didn't mean to jump the gun there

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0its ok, thats what I got too :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You have to factor out the 2 first, then work inside to complete the square.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is the point that i'm tryin to find to graph the parabola (4, 10)?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0no, its (2,4) as the vertex

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok thanks for your help

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I showed the work, so you can see where you went wrong.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0you have to factor out or divide out that 2 that is sitting in front of the x^2 before you can complete the square...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Just be sure to factor off any coefficients from your \(x^2\) term
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