anonymous
  • anonymous
A ball of radius 11 has a round hole of radius 7 drilled through its center. Find the volume of the resulting solid.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Find the volume of the ball and then subtract the volume of the hole.
anonymous
  • anonymous
that is what i have been trying. a ball is a sphere so v= 4/3r^3 and the hole is a cylinder pi*r^2*h but what is h the height it isnt the diameter of the sphere
anonymous
  • anonymous
The height is the the radius of the ball times 2 (Diameter) :)

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anonymous
  • anonymous
a cylindrical hole would be slightly shorter than the diameter of the sphere the thing is idk how to find that
anonymous
  • anonymous
If you are going to picture this out in your mind, or better yet, get a pen and paper and draw it.. You will find out that it is the height of sphere. Operative word is "center of the ball".
anonymous
  • anonymous
i did do that and i believe it was the diameter, but after some rethinking, as well as the answer being wrong i saw a different picture. Imagine a sphere. it is round obviously if you drill a hole threw it the the whole will be a cylinder. Cylinders have flat bases. A flat base would mean it cuts off before the end of the sphere. if the height was the diameter it would mean that the base is curved
anonymous
  • anonymous
afs brings a good point did you learn triple/double integrals yet? i believe that that is the only way to get the answer
anonymous
  • anonymous
Oh yeah! Figured that one out thanks for the clear description. @_@
anonymous
  • anonymous
We are at area between curves and volume between curves. i kind of know how to do those, but this, which is one of them, doesn't give all the info, all i need is the height and im good but dont know the height. :( @ mcometa :D
anonymous
  • anonymous
i think you can do this using what you do do you know the washer method yet?
anonymous
  • anonymous
i zoned out for that one, im using the shell method, but i dont know how exactly to apply it to this
anonymous
  • anonymous
ehh...i'm not sure what the shell method is LOL but the washer method is bascially integral curve1-curve2
anonymous
  • anonymous
Are you doing this in polar? or spherical?
anonymous
  • anonymous
And is this calc 3 or calc 2
anonymous
  • anonymous
so now imagine your cylinder and sphere on the xy plane ONLY the xy plane you'll see a circle and a rectangle curve1 will be the circle and curve2 will be the rectangle apply washer. this should work.
anonymous
  • anonymous
so the equation for the volume of a sphere - the volume of a cylinder? and @ polpak ? oh and calc 2
anonymous
  • anonymous
no
anonymous
  • anonymous
did what i just wrote make any sense?
anonymous
  • anonymous
lol i typed that before reading urs and yes it did i'll go ahead and try that ty :D
anonymous
  • anonymous
okay good luck rotate about y axis! cheers!

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