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anonymous
 5 years ago
z^2+8z+16/z^2100 times z^210z/z+4=
anonymous
 5 years ago
z^2+8z+16/z^2100 times z^210z/z+4=

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think the answer is 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(z^2+8z+16/z^2100)*(z^210z/z+4) = z^2*(z^210z/z+4)+8z*(z^210z/z+4)+16/z^2100*(z^210z/z+4) u can finish it right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lawd it looks even harder lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0z^2*(z^210z/z+4) = z^410z^3/z+4 8z*(z^210z/z+4) = 8z^380z^2/z+4 16/z^2100*(z^210z/z+4) = (16z^2/z^2100)(160z/(z^2100)(z+4)) from this is easier

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it doesn't nave to be solved simplified

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and then what it has to be?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(z^2+8z+16/z^2100)*(z^210z/z+4) = z^2*(z^210z/z+4)+8z*(z^210z/z+4)+16/z^2100*(z^210z/z+4) =z^410z^3/z+4+8z^380z^2/z+4+(16z^2/z^2100)(160z/(z^2100)(z+4)) and you simplify by urself from this

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The problem statement seems to be: \[\frac{\left(z^2+8 z+16\right) \left(z^210 z\right)}{\left(z^2100\right) (z+4)} \] Both of the products in the Numertor can be factored as well as the first product of the Denominator. Factor and then simplify. \[\frac{(4+z)^2 (10+z) z}{(10+z) (10+z) (z+4)}=\frac{z (4+z)}{10+z}\]
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