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anonymous

  • 5 years ago

Find the angle between the given vectors to the nearest tenth of a degree: U=4i + 5j, V=7i - 4j

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  1. amistre64
    • 5 years ago
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    teh angle between vector is: cos(t) = U*V/|U||V|

  2. amistre64
    • 5 years ago
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    <4, 5> <7,-4> -------- 28 -20 = 8; so the top is 8;

  3. amistre64
    • 5 years ago
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    sqrt(16+25) * sqrt(49 + 16) is the bottom

  4. amistre64
    • 5 years ago
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    8 ----------; take the cos^-1 to get the angle sqrt(41*65)

  5. amistre64
    • 5 years ago
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    if its greater than the cos^1(7/sqrt(65)) you need to adjust for a different quadrant

  6. anonymous
    • 5 years ago
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    Wow, I did this problem like twice and couldn't get it, I put the wrong number in for the second i.....lol Thanks a bunch!!!

  7. anonymous
    • 5 years ago
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    It's 81.1 deg

  8. amistre64
    • 5 years ago
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    angle = 81.08; but check the other one :)

  9. amistre64
    • 5 years ago
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    that angle seems larger than ....your right, my senility kicked in for a moment lol

  10. anonymous
    • 5 years ago
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    XD

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