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anonymous
 5 years ago
Find the angle between the given vectors to the nearest tenth of a degree:
U=4i + 5j, V=7i  4j
anonymous
 5 years ago
Find the angle between the given vectors to the nearest tenth of a degree: U=4i + 5j, V=7i  4j

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1teh angle between vector is: cos(t) = U*V/UV

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1<4, 5> <7,4>  28 20 = 8; so the top is 8;

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1sqrt(16+25) * sqrt(49 + 16) is the bottom

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.18 ; take the cos^1 to get the angle sqrt(41*65)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1if its greater than the cos^1(7/sqrt(65)) you need to adjust for a different quadrant

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Wow, I did this problem like twice and couldn't get it, I put the wrong number in for the second i.....lol Thanks a bunch!!!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1angle = 81.08; but check the other one :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1that angle seems larger than ....your right, my senility kicked in for a moment lol
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