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anonymous
 5 years ago
r^6  3r^4 + 3r^2  1 = 0 .. How to solve this differential equation ???
anonymous
 5 years ago
r^6  3r^4 + 3r^2  1 = 0 .. How to solve this differential equation ???

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Factorise it if you want. Though it may be easier to let x = r^2 than factorise that (it's a standard expansion if you recognise it; if not you can find a factor (or three) by inspection). Then \[r = \pm \sqrt{x} \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohh yea i get it! thanks alot !

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2does this help r=1 multplicity 3 r=1 multplicity 3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0:) If you're interesting, it actually factorises it it's original for as: \[(r1)^3(r+1)^3 \] Which I think is quite quaint.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2i tried to factor don't look at that first part where i factor r^4 of the first two terms

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2i got lucky and synthetic division worked since all r all are rational zeros

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@myininaya. thanks it sure did help

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@newton. but u will have to factorise to get that answer, no ? we cant figure it out directly, can we ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[(r1)^3(r+1)^3 = 0 \iff r = \pm 1 \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes yes i get it. what i meant to say was that we will have to factorise the original expression using division to reach to this answer ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Not necessarily using division, you could compare coefficients of something.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(after spotting a few factors by inspection  in this case they are so obvious, but normally trying 2, 1, 1, 2 will get at least one)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2look i have something else if you didnt like synthetic

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0:D thanks alot. i get it

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2thats alot of work for one problem lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0haha yea that sure is. im highly obliged

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.2so none of the algebra I did needs explaining?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nope its quite clear :) i completely get it, thanks to you :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@myininaya. could you please repost your cal0009.pdf attachment. it won't open for me. thanks
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