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anonymous
 5 years ago
Assume a jar has 7 red marbles and 5 black marbles. Draw out 3 marbles with and without replacement. Find the requested probabilities.
(c) P(one red and two black marbles)
With replacement , without replacement .
(d) P(red on the first draw and black on the second draw and black on the third draw)
With replacement , without replacement .
anonymous
 5 years ago
Assume a jar has 7 red marbles and 5 black marbles. Draw out 3 marbles with and without replacement. Find the requested probabilities. (c) P(one red and two black marbles) With replacement , without replacement . (d) P(red on the first draw and black on the second draw and black on the third draw) With replacement , without replacement .

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What does with replacement mean?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0putting back in the jar

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh. I dunno about that, but without replacement is pretty easy.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i understand more of the with replacement but if you can help with the without replacement that would be good

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0For the first question of one red and two black we just want to know how many ways we can choose one red, and two black divided by how many ways we can choose 3 marbles from 12. So: \[\frac{{7 \choose 1} * {5 \choose 2}}{12 \choose 3}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No, 7 choose 1 = 7 5 choose 2 = 10 12 choose 3 = 220 So it is 70/220. Are you familiar with the choose function (and it's notation)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0was that without replacement?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you know how to do d?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0For the other one it's just (Probability of choosing a red)*(Probability of choosing a black)*(Probability of choosing a black) So (7/12) * (5*/11) * (4/10)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0140/1320....can be reduced though right?
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