need help finding the solution(s) to this equation..

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need help finding the solution(s) to this equation..

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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\[y ^{-1}-22^{-1 \over 2}+120=0\]
1/y -(sqrt[22])+120 = 0 y = 1/(sqrt[22]-120)
wrong 1/y -(1/(sqrt[22]))+120 = 0 1/y = (1/(sqrt(22) - 120) = (1-120*sqrt[22])/sqrt[22]) y = sqrt[22]/(1-120sqrt[22])

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wait, so the first thing you wrote is wrong. But this second one is right?
yep
oh ok, so there is only one answer? \[\sqrt{22}\over 1-120\sqrt{22}\] is this correct?
the line didn't show up but it's supposed to be a fraction
he left :(. Polpak, does that look correct to you?
Sorry, one sec
\[\frac{1}{y} - \frac{1}{\sqrt{22}} + 120 = 0\] \[\implies \frac{1}{y} = \frac{1}{\sqrt{22}} - 120\] \[\implies \frac{1}{y} = \frac{1}{\sqrt{22}} - \frac{120\sqrt{22}}{\sqrt{22}}\] \[\implies \frac{1}{y} = \frac{1-120\sqrt{22}}{\sqrt{22}}\] \[\implies y =\frac{\sqrt{22}}{1-120\sqrt{22}} \]
Yeah, that's correct
can i get some help again please..
the root 22 on the bottom part wouldn't type in my online assignment.. so it must not be there..
Are you certain the original equation is correct?
i will double check.
wow. I don't know why i keep doing that..but I forgot the y.. it is all the same except there is a y after the 22
\[y ^{-1}-22y ^{-1 \over 2}+120=0\]
sorry!!
Ah, that's nicer certainly.

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