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anonymous

  • 5 years ago

need help finding the solution(s) to this equation..

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  1. anonymous
    • 5 years ago
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    \[y ^{-1}-22^{-1 \over 2}+120=0\]

  2. anonymous
    • 5 years ago
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    1/y -(sqrt[22])+120 = 0 y = 1/(sqrt[22]-120)

  3. anonymous
    • 5 years ago
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    wrong 1/y -(1/(sqrt[22]))+120 = 0 1/y = (1/(sqrt(22) - 120) = (1-120*sqrt[22])/sqrt[22]) y = sqrt[22]/(1-120sqrt[22])

  4. anonymous
    • 5 years ago
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    wait, so the first thing you wrote is wrong. But this second one is right?

  5. anonymous
    • 5 years ago
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    yep

  6. anonymous
    • 5 years ago
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    oh ok, so there is only one answer? \[\sqrt{22}\over 1-120\sqrt{22}\] is this correct?

  7. anonymous
    • 5 years ago
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    the line didn't show up but it's supposed to be a fraction

  8. anonymous
    • 5 years ago
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    he left :(. Polpak, does that look correct to you?

  9. anonymous
    • 5 years ago
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    Sorry, one sec

  10. anonymous
    • 5 years ago
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    \[\frac{1}{y} - \frac{1}{\sqrt{22}} + 120 = 0\] \[\implies \frac{1}{y} = \frac{1}{\sqrt{22}} - 120\] \[\implies \frac{1}{y} = \frac{1}{\sqrt{22}} - \frac{120\sqrt{22}}{\sqrt{22}}\] \[\implies \frac{1}{y} = \frac{1-120\sqrt{22}}{\sqrt{22}}\] \[\implies y =\frac{\sqrt{22}}{1-120\sqrt{22}} \]

  11. anonymous
    • 5 years ago
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    Yeah, that's correct

  12. anonymous
    • 5 years ago
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    can i get some help again please..

  13. anonymous
    • 5 years ago
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    the root 22 on the bottom part wouldn't type in my online assignment.. so it must not be there..

  14. anonymous
    • 5 years ago
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    Are you certain the original equation is correct?

  15. anonymous
    • 5 years ago
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    i will double check.

  16. anonymous
    • 5 years ago
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    wow. I don't know why i keep doing that..but I forgot the y.. it is all the same except there is a y after the 22

  17. anonymous
    • 5 years ago
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    \[y ^{-1}-22y ^{-1 \over 2}+120=0\]

  18. anonymous
    • 5 years ago
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    sorry!!

  19. anonymous
    • 5 years ago
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    Ah, that's nicer certainly.

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spraguer (Moderator)
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