I need some help on finding the solution, an ordered pair using the substitution method
3m + n = 1
m-5n = 11 can anyone help and explain I get so far and I am confused

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so n = 1-3m
m-5(1-3m) = 11
m-5+15m = 11
16m = 16
m=1.
n = 1-3(1) = -2
n=-2

this is where i get confused

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