need help finding the solution(s) to this equation..

- anonymous

need help finding the solution(s) to this equation..

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- anonymous

\[y ^{-1}-22y ^{-1 \over 2}+120=0\]

- myininaya

let u=y^(-1/2)

- myininaya

so what does u^2=?

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## More answers

- anonymous

x?

- myininaya

u^2=y^(-1)

- anonymous

ok, thanks. so where do I go from here?

- myininaya

do you know how to factor u^2-22u+120=0

- anonymous

i'm trying to figure out what works for 22 and 120..does anything besides 2 go into them both?

- myininaya

(u-10)(u-12)=0

- anonymous

so will the 2 solutions be positive 10 and 12 then?

- myininaya

y^(-1/2)=10
y^(-1/2)=12
since u=y^(-1/2)

- myininaya

solve for y from both of these equations and you are done

- anonymous

would it be 10 1/2 and 12 1/2 then? i didn't know the solutions could be anything besides a whole numbers

- myininaya

y=10^(-2)
y=12^(-2)
you can evaluate those

- anonymous

Sorry I have so many questions..I just want to make sure I understand completely. To evaluate these what exactly do i do?

- myininaya

do you know law of exponents?

- anonymous

possibly. I'm not sure exactly what that entails. I don't know the tnames for all these math terms

- myininaya

y=10^(-2)=1/(10^2)
y=12^(-2)=1/(12^2)
can you evaluate it now?

- anonymous

do they just end up being 10 and 12?

- myininaya

y=1/(10*10)
y=1/(12*12)
can you evaluate these now?

- anonymous

100 and 144?

- anonymous

I just didn't think it would be that large of number.

- myininaya

y=1/100
y=1/144

- myininaya

you can plug these in to check if you want

- anonymous

oh the 1 does stay on top? wasn't sure about that. Sorry i'm so incompetent at math.

- anonymous

Ok will do. thanks

- myininaya

np how about a medal? lol

- anonymous

i'd say you earned it!

- myininaya

yay! :)

- myininaya

thanks you i will give you one too

- anonymous

yay! Idk if i deserve one but thanks anyways! :)

- myininaya

lol ok deserve it here if we have the function f(n)=2
find f(3)=...

- anonymous

2..or n...er.. uhh

- myininaya

lol thats right

- anonymous

woohoo!

- myininaya

the 2 is right

- myininaya

its a horizontal line going through the y axis at 2 so no matter what you plug in fir x (or n) you will always get 2

- myininaya

have a goodnight

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