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anonymous

  • 5 years ago

need help finding the solution(s) to this equation..

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  1. anonymous
    • 5 years ago
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    \[y ^{-1}-22y ^{-1 \over 2}+120=0\]

  2. myininaya
    • 5 years ago
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    let u=y^(-1/2)

  3. myininaya
    • 5 years ago
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    so what does u^2=?

  4. anonymous
    • 5 years ago
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    x?

  5. myininaya
    • 5 years ago
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    u^2=y^(-1)

  6. anonymous
    • 5 years ago
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    ok, thanks. so where do I go from here?

  7. myininaya
    • 5 years ago
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    do you know how to factor u^2-22u+120=0

  8. anonymous
    • 5 years ago
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    i'm trying to figure out what works for 22 and 120..does anything besides 2 go into them both?

  9. myininaya
    • 5 years ago
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    (u-10)(u-12)=0

  10. anonymous
    • 5 years ago
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    so will the 2 solutions be positive 10 and 12 then?

  11. myininaya
    • 5 years ago
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    y^(-1/2)=10 y^(-1/2)=12 since u=y^(-1/2)

  12. myininaya
    • 5 years ago
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    solve for y from both of these equations and you are done

  13. anonymous
    • 5 years ago
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    would it be 10 1/2 and 12 1/2 then? i didn't know the solutions could be anything besides a whole numbers

  14. myininaya
    • 5 years ago
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    y=10^(-2) y=12^(-2) you can evaluate those

  15. anonymous
    • 5 years ago
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    Sorry I have so many questions..I just want to make sure I understand completely. To evaluate these what exactly do i do?

  16. myininaya
    • 5 years ago
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    do you know law of exponents?

  17. anonymous
    • 5 years ago
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    possibly. I'm not sure exactly what that entails. I don't know the tnames for all these math terms

  18. myininaya
    • 5 years ago
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    y=10^(-2)=1/(10^2) y=12^(-2)=1/(12^2) can you evaluate it now?

  19. anonymous
    • 5 years ago
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    do they just end up being 10 and 12?

  20. myininaya
    • 5 years ago
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    y=1/(10*10) y=1/(12*12) can you evaluate these now?

  21. anonymous
    • 5 years ago
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    100 and 144?

  22. anonymous
    • 5 years ago
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    I just didn't think it would be that large of number.

  23. myininaya
    • 5 years ago
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    y=1/100 y=1/144

  24. myininaya
    • 5 years ago
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    you can plug these in to check if you want

  25. anonymous
    • 5 years ago
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    oh the 1 does stay on top? wasn't sure about that. Sorry i'm so incompetent at math.

  26. anonymous
    • 5 years ago
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    Ok will do. thanks

  27. myininaya
    • 5 years ago
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    np how about a medal? lol

  28. anonymous
    • 5 years ago
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    i'd say you earned it!

  29. myininaya
    • 5 years ago
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    yay! :)

  30. myininaya
    • 5 years ago
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    thanks you i will give you one too

  31. anonymous
    • 5 years ago
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    yay! Idk if i deserve one but thanks anyways! :)

  32. myininaya
    • 5 years ago
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    lol ok deserve it here if we have the function f(n)=2 find f(3)=...

  33. anonymous
    • 5 years ago
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    2..or n...er.. uhh

  34. myininaya
    • 5 years ago
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    lol thats right

  35. anonymous
    • 5 years ago
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    woohoo!

  36. myininaya
    • 5 years ago
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    the 2 is right

  37. myininaya
    • 5 years ago
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    its a horizontal line going through the y axis at 2 so no matter what you plug in fir x (or n) you will always get 2

  38. myininaya
    • 5 years ago
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    have a goodnight

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