anonymous
  • anonymous
need help finding the solution(s) to this equation..
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[y ^{-1}-22y ^{-1 \over 2}+120=0\]
myininaya
  • myininaya
let u=y^(-1/2)
myininaya
  • myininaya
so what does u^2=?

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anonymous
  • anonymous
x?
myininaya
  • myininaya
u^2=y^(-1)
anonymous
  • anonymous
ok, thanks. so where do I go from here?
myininaya
  • myininaya
do you know how to factor u^2-22u+120=0
anonymous
  • anonymous
i'm trying to figure out what works for 22 and 120..does anything besides 2 go into them both?
myininaya
  • myininaya
(u-10)(u-12)=0
anonymous
  • anonymous
so will the 2 solutions be positive 10 and 12 then?
myininaya
  • myininaya
y^(-1/2)=10 y^(-1/2)=12 since u=y^(-1/2)
myininaya
  • myininaya
solve for y from both of these equations and you are done
anonymous
  • anonymous
would it be 10 1/2 and 12 1/2 then? i didn't know the solutions could be anything besides a whole numbers
myininaya
  • myininaya
y=10^(-2) y=12^(-2) you can evaluate those
anonymous
  • anonymous
Sorry I have so many questions..I just want to make sure I understand completely. To evaluate these what exactly do i do?
myininaya
  • myininaya
do you know law of exponents?
anonymous
  • anonymous
possibly. I'm not sure exactly what that entails. I don't know the tnames for all these math terms
myininaya
  • myininaya
y=10^(-2)=1/(10^2) y=12^(-2)=1/(12^2) can you evaluate it now?
anonymous
  • anonymous
do they just end up being 10 and 12?
myininaya
  • myininaya
y=1/(10*10) y=1/(12*12) can you evaluate these now?
anonymous
  • anonymous
100 and 144?
anonymous
  • anonymous
I just didn't think it would be that large of number.
myininaya
  • myininaya
y=1/100 y=1/144
myininaya
  • myininaya
you can plug these in to check if you want
anonymous
  • anonymous
oh the 1 does stay on top? wasn't sure about that. Sorry i'm so incompetent at math.
anonymous
  • anonymous
Ok will do. thanks
myininaya
  • myininaya
np how about a medal? lol
anonymous
  • anonymous
i'd say you earned it!
myininaya
  • myininaya
yay! :)
myininaya
  • myininaya
thanks you i will give you one too
anonymous
  • anonymous
yay! Idk if i deserve one but thanks anyways! :)
myininaya
  • myininaya
lol ok deserve it here if we have the function f(n)=2 find f(3)=...
anonymous
  • anonymous
2..or n...er.. uhh
myininaya
  • myininaya
lol thats right
anonymous
  • anonymous
woohoo!
myininaya
  • myininaya
the 2 is right
myininaya
  • myininaya
its a horizontal line going through the y axis at 2 so no matter what you plug in fir x (or n) you will always get 2
myininaya
  • myininaya
have a goodnight

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