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anonymous

  • 5 years ago

Find the equation of a polynomial that has the roots 3,2, and -1 and goes through the point 1,1

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  1. anonymous
    • 5 years ago
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    reverse engineer the quadratic equation to fit specs

  2. dumbcow
    • 5 years ago
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    y = a(x-3)(x-2)(x+1)

  3. anonymous
    • 5 years ago
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    @ dumbcow What do I do with "a"?

  4. dumbcow
    • 5 years ago
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    its a constant we solve for it by putting in the x and y values from the point (1,1) 1=a(1-3)(1-2)(1+1)

  5. anonymous
    • 5 years ago
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    Oh I see. I thought I could just add one on to the equation y=(X-3).... This makes sense. Thank you.

  6. dumbcow
    • 5 years ago
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    no problem

  7. anonymous
    • 5 years ago
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    @ dumbcow. Just finished the problem... It works!

  8. anonymous
    • 5 years ago
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    u could also use -b/a = x1+x2 and c/a = x1x2 and solve for a and b or c then use the fact that f[1]=1 to find c or b

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