anonymous
  • anonymous
Last problem for the night! Help? Please and thank you :)
Mathematics
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anonymous
  • anonymous
Last problem for the night! Help? Please and thank you :)
Mathematics
katieb
  • katieb
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
\[y ^{-2}-13y ^{-1}+40=0\]
anonymous
  • anonymous
I will start understanding this stuff sooner or later :/
amistre64
  • amistre64
a = 1/y y = 13/2 +- sqrt(13^2 -4(40))/2

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amistre64
  • amistre64
a = ..... not y lol
amistre64
  • amistre64
a = 13/2 +- 3/2
anonymous
  • anonymous
Eh. Let \(u = y^{-1} \implies u^2 - y^{-2} \) Then solve the quadratic the way you usually do \[u^2-13u +40 = 0\]
amistre64
  • amistre64
a = 16/2 = 8 a = 10/2 = 5
amistre64
  • amistre64
8 = 1/y ; y=1/8 5 = 1/y ; y = 1/5
anonymous
  • anonymous
1/8 and 1/5 it is. I will try it out! Thanks

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