can anyone help me with complex fractions?

- anonymous

can anyone help me with complex fractions?

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- schrodinger

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- anonymous

Yes.

- anonymous

okay should i give you the problems I have? I have three problems to do tonight.

- anonymous

Yes.

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## More answers

- amistre64

you can always keep them to yourself and make us guess ;)

- nowhereman

In most of the cases all you have to do is use the third binomial formula for the denominator to make it real and then separate real and imaginary part in the numerator

- anonymous

hahaha :) well i just joined this site so i didn't know if people are willing to do my math problems if i post them. thank you nowhereman..but these problems are a few i have left over that ive been attempting to do so many times and failing horribly. so i figure this is my best bet. here is the first question

- anonymous

4/81-1/x^2
-------------
1/9+1/x
(the dotted line separates the num from denom

- anonymous

z=5

- anonymous

?

- anonymous

z?

- nowhereman

Are you sure it's a 4? because then you can only expand it by 81x^2 and not really simlify it much

- amistre64

complex means something else in math terms :)

- amistre64

get 81x^2 as common denoms

- amistre64

4x^2-81
---------
2x^2+81x

- nowhereman

you mean 9 instead of 2, don't you?

- amistre64

2x^2(9) ...yeah lol

- amistre64

(2x-9)(2x+9)
-------------
9x(x+9)

- anonymous

yes! thank you so much! i have two more for you =]

- amistre64

is that correct? lol

- anonymous

YES it is correct you awesome awesome person

- amistre64

nowhere helped ;)

- anonymous

yes, thanks to both of you!

- amistre64

he like my jiminy cricket; ..do this, do that; why do i bother lol

- anonymous

x/7 - 7/x
---------
4/7 - 4/x

- amistre64

7x as commons

- anonymous

hahaha you are silly. that's a great analogy. does he follow what you say to other people often, correcting what you say?

- amistre64

they all do; they point out all my flaws in a vain attenpt to keep me humble ;)

- anonymous

hehehe keeps you in check

- amistre64

x^2 - 49
-------
4x - 28
(x+7)(x-7)
--------- = (x+7)/4
4(x - 7)

- anonymous

that is what i got :)
thank you

- anonymous

(16/x-3) + 8
-------------
(10/x-3) +5

- amistre64

is that x-3 all inthe denominator?

- anonymous

both of the x-3s are in each of the denominators. the +8 and +5 are not. does that make sense?

- anonymous

multiply numerator and denominator by the factor x-3

- anonymous

16+8(x-3)
------------
10+5(x-3)

- amistre64

(x-3) for common denoms then:
16/(x-3) + 8
-------------
10/(x-3) +5
16 + 8x - 24
-------------
10 +5x - 15
8x - 8
------
5x - 5
8(x - 1)
------- = 8/5
5(x - 1)

- anonymous

16+8x-24
---------
10+5x-15

- anonymous

so those x-1's cancel out ?

- anonymous

yes right :)

- amistre64

its either that or we use them for beef stew stock lol

- anonymous

lol you're fricken hilarious dude. thanks you guys! i can sleep peacefully now!

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