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anonymous

  • 5 years ago

can anyone help me with complex fractions?

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  1. anonymous
    • 5 years ago
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    Yes.

  2. anonymous
    • 5 years ago
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    okay should i give you the problems I have? I have three problems to do tonight.

  3. anonymous
    • 5 years ago
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    Yes.

  4. amistre64
    • 5 years ago
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    you can always keep them to yourself and make us guess ;)

  5. nowhereman
    • 5 years ago
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    In most of the cases all you have to do is use the third binomial formula for the denominator to make it real and then separate real and imaginary part in the numerator

  6. anonymous
    • 5 years ago
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    hahaha :) well i just joined this site so i didn't know if people are willing to do my math problems if i post them. thank you nowhereman..but these problems are a few i have left over that ive been attempting to do so many times and failing horribly. so i figure this is my best bet. here is the first question

  7. anonymous
    • 5 years ago
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    4/81-1/x^2 ------------- 1/9+1/x (the dotted line separates the num from denom

  8. anonymous
    • 5 years ago
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    z=5

  9. anonymous
    • 5 years ago
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    ?

  10. anonymous
    • 5 years ago
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    z?

  11. nowhereman
    • 5 years ago
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    Are you sure it's a 4? because then you can only expand it by 81x^2 and not really simlify it much

  12. amistre64
    • 5 years ago
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    complex means something else in math terms :)

  13. amistre64
    • 5 years ago
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    get 81x^2 as common denoms

  14. amistre64
    • 5 years ago
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    4x^2-81 --------- 2x^2+81x

  15. nowhereman
    • 5 years ago
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    you mean 9 instead of 2, don't you?

  16. amistre64
    • 5 years ago
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    2x^2(9) ...yeah lol

  17. amistre64
    • 5 years ago
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    (2x-9)(2x+9) ------------- 9x(x+9)

  18. anonymous
    • 5 years ago
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    yes! thank you so much! i have two more for you =]

  19. amistre64
    • 5 years ago
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    is that correct? lol

  20. anonymous
    • 5 years ago
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    YES it is correct you awesome awesome person

  21. amistre64
    • 5 years ago
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    nowhere helped ;)

  22. anonymous
    • 5 years ago
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    yes, thanks to both of you!

  23. amistre64
    • 5 years ago
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    he like my jiminy cricket; ..do this, do that; why do i bother lol

  24. anonymous
    • 5 years ago
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    x/7 - 7/x --------- 4/7 - 4/x

  25. amistre64
    • 5 years ago
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    7x as commons

  26. anonymous
    • 5 years ago
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    hahaha you are silly. that's a great analogy. does he follow what you say to other people often, correcting what you say?

  27. amistre64
    • 5 years ago
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    they all do; they point out all my flaws in a vain attenpt to keep me humble ;)

  28. anonymous
    • 5 years ago
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    hehehe keeps you in check

  29. amistre64
    • 5 years ago
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    x^2 - 49 ------- 4x - 28 (x+7)(x-7) --------- = (x+7)/4 4(x - 7)

  30. anonymous
    • 5 years ago
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    that is what i got :) thank you

  31. anonymous
    • 5 years ago
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    (16/x-3) + 8 ------------- (10/x-3) +5

  32. amistre64
    • 5 years ago
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    is that x-3 all inthe denominator?

  33. anonymous
    • 5 years ago
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    both of the x-3s are in each of the denominators. the +8 and +5 are not. does that make sense?

  34. anonymous
    • 5 years ago
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    multiply numerator and denominator by the factor x-3

  35. anonymous
    • 5 years ago
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    16+8(x-3) ------------ 10+5(x-3)

  36. amistre64
    • 5 years ago
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    (x-3) for common denoms then: 16/(x-3) + 8 ------------- 10/(x-3) +5 16 + 8x - 24 ------------- 10 +5x - 15 8x - 8 ------ 5x - 5 8(x - 1) ------- = 8/5 5(x - 1)

  37. anonymous
    • 5 years ago
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    16+8x-24 --------- 10+5x-15

  38. anonymous
    • 5 years ago
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    so those x-1's cancel out ?

  39. anonymous
    • 5 years ago
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    yes right :)

  40. amistre64
    • 5 years ago
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    its either that or we use them for beef stew stock lol

  41. anonymous
    • 5 years ago
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    lol you're fricken hilarious dude. thanks you guys! i can sleep peacefully now!

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