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anonymous
 5 years ago
let A = [ 1 2 3 4: 5 6 7 8: 1 2 3 4: 5 6 7 8] as a 4x4 matrix
find a basis for the vectorspace NullA
anonymous
 5 years ago
let A = [ 1 2 3 4: 5 6 7 8: 1 2 3 4: 5 6 7 8] as a 4x4 matrix find a basis for the vectorspace NullA

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i used question 8 on this link: http://abacus.bates.edu/~etowne/031811jayawant205examsoln.pdf as a point of reference, but I'm unsure how to handle two free variables

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0we reduce the matrix to reduced echelon form

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0[(1 0 1 2 \ 0 1 2 3 \ 0 0 0 0\0 0 0 0)\] which shows two free variables, and that x(1) = x(3) +2x(4) and x(2) = 2x(3)3x(4)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there r two nonzero rows, mean that rank=2 since we have rank + nullity =4(order of the matrix) nullity=2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then does the question even make sense to find the basis for that vectorspace?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0u mean the given matrix?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the link i posted shows how they solved for a 3x3 with one free variable, but im unsure how to proceed with two

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh i didnt check it:)
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