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anonymous

  • 5 years ago

OMG i need help, I'm working on Rational expression: 7- a-2/a+3 = a(squared)-4/a+3 +5.. anyone?

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  1. anonymous
    • 5 years ago
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    [7-(a-2/a+3)]=[(a^2-4)/a+3)+5] right?

  2. anonymous
    • 5 years ago
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    is it:\[7 - \frac{a-2}{a+3} = \frac{a^2-4}{a+3} + 5\]?

  3. anonymous
    • 5 years ago
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    sstarica how you write that symbols

  4. anonymous
    • 5 years ago
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    using the equation button down-left on your past box :)

  5. anonymous
    • 5 years ago
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    post*

  6. anonymous
    • 5 years ago
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    yes that is it! ok i see the equation button

  7. anonymous
    • 5 years ago
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    I did try but I can write the faction

  8. anonymous
    • 5 years ago
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    i know the answer but i have no idea how they got it im so stomped

  9. anonymous
    • 5 years ago
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    use frac{}{} for the fraction :), alright, if that's your question then the answer is the following

  10. anonymous
    • 5 years ago
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    \[7+5 - \frac{(a-2)}{a+3} - \frac{(a^2-4)}{a+3} = 0\]\[\frac{12(a+3) - a + 2 - a^2 + 4}{a+3} = \frac{12a + 36 - a + 2 - a^2 + 4}{a+3}\]\[= \frac{-a^2-11a+42}{a+3} = \frac{-(a^2+11a-42)}{a+3}\]\[= \frac{-(a+3)(a-14)}{a+3} = -(a-14) \rightarrow -a+14\] Correct me if I'm wrong ^_^

  11. anonymous
    • 5 years ago
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    wait, it's 11 a and not -11 a ^_^" sorry

  12. anonymous
    • 5 years ago
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    humm the book has an answer of 4 only, I am confused

  13. anonymous
    • 5 years ago
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    so :\[= \frac{-a^2 + 11a +42}{a+3}\]\[= \frac{-(a^2-11a-42)}{a-3} = \frac{-(a+3)(a-14)}{a+3}\] I just messed up the sign of 11, so in the end when you simplify you'll get -a+14, I guess

  14. anonymous
    • 5 years ago
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    4? weird

  15. anonymous
    • 5 years ago
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    a = 14 in this case?

  16. anonymous
    • 5 years ago
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    yeah, it gives x=4 only

  17. anonymous
    • 5 years ago
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    x? but we are dealing with a here

  18. anonymous
    • 5 years ago
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    im sorry a yes

  19. anonymous
    • 5 years ago
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    lol, that's weird.

  20. anonymous
    • 5 years ago
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    hang on

  21. anonymous
    • 5 years ago
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    what i did was mutliply each side by (a+3)

  22. anonymous
    • 5 years ago
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    so i ended up with

  23. anonymous
    • 5 years ago
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    I GOT IT!

  24. anonymous
    • 5 years ago
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    the answer IS 4 lol

  25. anonymous
    • 5 years ago
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    steps:

  26. anonymous
    • 5 years ago
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    7(a+3) - a - 2 = a^{2}-4 + 5(a+3)

  27. anonymous
    • 5 years ago
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    ok show me please..lol

  28. anonymous
    • 5 years ago
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    \[\frac{-(a-2)}{a+3} - \frac{a^2-4}{a+3} = 5-7\]\[\frac{-a^2-a-6}{a+3} = -2\]\[\frac{-(a^2+a-6)}{a+3} = -2\]\[\frac{-(a-2)(a+3)}{a+3} = -2\]\[-(a-2) = -2 \rightarrow -a +2 = -2\]\[-a = -4 \rightarrow a = 4\] ^_^

  29. anonymous
    • 5 years ago
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    lol in the 2nd line it's supposed to be + 6, but just a small typo, doesn't effect the solution :)

  30. anonymous
    • 5 years ago
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    so ur first step was to subtract the entire fraction from one side?

  31. anonymous
    • 5 years ago
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    yes, I moved 7 to the other side and got all the a's in one side :) and started solving for a ^_^

  32. anonymous
    • 5 years ago
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    oh i didnt know you could do that

  33. anonymous
    • 5 years ago
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    lol, it's like solving for x: 4x -3 = x + 2, solve for x <-- move the x's in one side and numbers in one side ^_^

  34. anonymous
    • 5 years ago
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    and now since both fractions have the same denominator i can simply subtrat the entire top row

  35. anonymous
    • 5 years ago
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    yep :)

  36. anonymous
    • 5 years ago
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    wait what happend to the (a+3) how did that cancel?

  37. anonymous
    • 5 years ago
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    you simplified, cancel the (a+3) from top and bottom ^_^

  38. anonymous
    • 5 years ago
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    and you'll be left with only -(a-2) :)

  39. anonymous
    • 5 years ago
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    ok perfect, i got it, then when you divde at the end the two -1's cancel out and -4/-1 = postitive 4.. haha perfect

  40. anonymous
    • 5 years ago
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    yep ^_^

  41. anonymous
    • 5 years ago
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    next time don't panic :P and face the problem calmly ^_^ good luck!

  42. anonymous
    • 5 years ago
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    thank you, it just never crossed my mind that i could move the entire fraction, i was so worried about mutliplying every side the the LCD that i got stuck on it for an hour.. thank you!

  43. anonymous
    • 5 years ago
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    my answer: (7*(a+3))-(a-2)=(a^2-4)+(5*(a+3) (7a+21)-(a-2)=(a^2-4)+(5a+15) 6a+23=a^2+5a+11 a^2-a-12=0 Factor:(a+3)(a-4)

  44. anonymous
    • 5 years ago
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    you are most welcome ^_^, worrying = distracts you from concentrating. Look at it as simple as possible then you'll be able to solve it :)

  45. anonymous
    • 5 years ago
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    hmm, nancy lam's solution seems simple too :)

  46. anonymous
    • 5 years ago
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    nancy ur answer works too i think, its that x would = -3 which would be no solution, but the x=4 would work

  47. anonymous
    • 5 years ago
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    but I don't know write like you see better

  48. anonymous
    • 5 years ago
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    as long as the denominator isn't zero, from what i remember in class

  49. anonymous
    • 5 years ago
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    2 solution , and lug it in to see which one work

  50. anonymous
    • 5 years ago
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    i was doing it your way nancy, but somehow, i got messed up with my signs

  51. anonymous
    • 5 years ago
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    u got rid of the denominator right from the beginning which is what i was trying to do im going to work it over again and see where i messed up

  52. anonymous
    • 5 years ago
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    I working write fraction like sstarica

  53. anonymous
    • 5 years ago
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    you time (a+3) for which one don't have denominator and get rid all denominator from beginning

  54. anonymous
    • 5 years ago
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    ok, bye

  55. anonymous
    • 5 years ago
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    Thank you, both of you! now i can sleep!

  56. anonymous
    • 5 years ago
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    you wellcome

  57. anonymous
    • 5 years ago
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    np :)

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