anonymous
  • anonymous
OMG i need help, I'm working on Rational expression: 7- a-2/a+3 = a(squared)-4/a+3 +5.. anyone?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
[7-(a-2/a+3)]=[(a^2-4)/a+3)+5] right?
anonymous
  • anonymous
is it:\[7 - \frac{a-2}{a+3} = \frac{a^2-4}{a+3} + 5\]?
anonymous
  • anonymous
sstarica how you write that symbols

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anonymous
  • anonymous
using the equation button down-left on your past box :)
anonymous
  • anonymous
post*
anonymous
  • anonymous
yes that is it! ok i see the equation button
anonymous
  • anonymous
I did try but I can write the faction
anonymous
  • anonymous
i know the answer but i have no idea how they got it im so stomped
anonymous
  • anonymous
use frac{}{} for the fraction :), alright, if that's your question then the answer is the following
anonymous
  • anonymous
\[7+5 - \frac{(a-2)}{a+3} - \frac{(a^2-4)}{a+3} = 0\]\[\frac{12(a+3) - a + 2 - a^2 + 4}{a+3} = \frac{12a + 36 - a + 2 - a^2 + 4}{a+3}\]\[= \frac{-a^2-11a+42}{a+3} = \frac{-(a^2+11a-42)}{a+3}\]\[= \frac{-(a+3)(a-14)}{a+3} = -(a-14) \rightarrow -a+14\] Correct me if I'm wrong ^_^
anonymous
  • anonymous
wait, it's 11 a and not -11 a ^_^" sorry
anonymous
  • anonymous
humm the book has an answer of 4 only, I am confused
anonymous
  • anonymous
so :\[= \frac{-a^2 + 11a +42}{a+3}\]\[= \frac{-(a^2-11a-42)}{a-3} = \frac{-(a+3)(a-14)}{a+3}\] I just messed up the sign of 11, so in the end when you simplify you'll get -a+14, I guess
anonymous
  • anonymous
4? weird
anonymous
  • anonymous
a = 14 in this case?
anonymous
  • anonymous
yeah, it gives x=4 only
anonymous
  • anonymous
x? but we are dealing with a here
anonymous
  • anonymous
im sorry a yes
anonymous
  • anonymous
lol, that's weird.
anonymous
  • anonymous
hang on
anonymous
  • anonymous
what i did was mutliply each side by (a+3)
anonymous
  • anonymous
so i ended up with
anonymous
  • anonymous
I GOT IT!
anonymous
  • anonymous
the answer IS 4 lol
anonymous
  • anonymous
steps:
anonymous
  • anonymous
7(a+3) - a - 2 = a^{2}-4 + 5(a+3)
anonymous
  • anonymous
ok show me please..lol
anonymous
  • anonymous
\[\frac{-(a-2)}{a+3} - \frac{a^2-4}{a+3} = 5-7\]\[\frac{-a^2-a-6}{a+3} = -2\]\[\frac{-(a^2+a-6)}{a+3} = -2\]\[\frac{-(a-2)(a+3)}{a+3} = -2\]\[-(a-2) = -2 \rightarrow -a +2 = -2\]\[-a = -4 \rightarrow a = 4\] ^_^
anonymous
  • anonymous
lol in the 2nd line it's supposed to be + 6, but just a small typo, doesn't effect the solution :)
anonymous
  • anonymous
so ur first step was to subtract the entire fraction from one side?
anonymous
  • anonymous
yes, I moved 7 to the other side and got all the a's in one side :) and started solving for a ^_^
anonymous
  • anonymous
oh i didnt know you could do that
anonymous
  • anonymous
lol, it's like solving for x: 4x -3 = x + 2, solve for x <-- move the x's in one side and numbers in one side ^_^
anonymous
  • anonymous
and now since both fractions have the same denominator i can simply subtrat the entire top row
anonymous
  • anonymous
yep :)
anonymous
  • anonymous
wait what happend to the (a+3) how did that cancel?
anonymous
  • anonymous
you simplified, cancel the (a+3) from top and bottom ^_^
anonymous
  • anonymous
and you'll be left with only -(a-2) :)
anonymous
  • anonymous
ok perfect, i got it, then when you divde at the end the two -1's cancel out and -4/-1 = postitive 4.. haha perfect
anonymous
  • anonymous
yep ^_^
anonymous
  • anonymous
next time don't panic :P and face the problem calmly ^_^ good luck!
anonymous
  • anonymous
thank you, it just never crossed my mind that i could move the entire fraction, i was so worried about mutliplying every side the the LCD that i got stuck on it for an hour.. thank you!
anonymous
  • anonymous
my answer: (7*(a+3))-(a-2)=(a^2-4)+(5*(a+3) (7a+21)-(a-2)=(a^2-4)+(5a+15) 6a+23=a^2+5a+11 a^2-a-12=0 Factor:(a+3)(a-4)
anonymous
  • anonymous
you are most welcome ^_^, worrying = distracts you from concentrating. Look at it as simple as possible then you'll be able to solve it :)
anonymous
  • anonymous
hmm, nancy lam's solution seems simple too :)
anonymous
  • anonymous
nancy ur answer works too i think, its that x would = -3 which would be no solution, but the x=4 would work
anonymous
  • anonymous
but I don't know write like you see better
anonymous
  • anonymous
as long as the denominator isn't zero, from what i remember in class
anonymous
  • anonymous
2 solution , and lug it in to see which one work
anonymous
  • anonymous
i was doing it your way nancy, but somehow, i got messed up with my signs
anonymous
  • anonymous
u got rid of the denominator right from the beginning which is what i was trying to do im going to work it over again and see where i messed up
anonymous
  • anonymous
I working write fraction like sstarica
anonymous
  • anonymous
you time (a+3) for which one don't have denominator and get rid all denominator from beginning
anonymous
  • anonymous
ok, bye
anonymous
  • anonymous
Thank you, both of you! now i can sleep!
anonymous
  • anonymous
you wellcome
anonymous
  • anonymous
np :)

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