anonymous
  • anonymous
a boat traveled 45 miles downstream (w/ the current) in 3 hours and made the return trip (against the current) in 5 hours. what was the speed of the boat and what was the speed of the current?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
When the boat is travelling in the direction of the current, the velocity of the boat coincides with the velocity of the current, so the net speed of the boat is c + b and since it takes 3 hours to travel 45 miles, we have, 3(c+b) = 45 ___(1) When the boat moves against the current, the velocity of the boat is in the opposite direction, so the net velocity of the boat is c-b and since it takes 5 hours to travel back 45 miles, we have, 5(c-b) = 45 ___(2) You have two linear equations in two unknowns, which you can solve.
anonymous
  • anonymous
3c+3b=45 --> c+b=15 ...(3) 5c-5b=45 --> c-b=9 ...(4) Add (3) to (4): 2c=24 --> c = 12 Subtract (4) from (3): 2b=6 --> b=3.
anonymous
  • anonymous
ok thank you so much lokisan

Looking for something else?

Not the answer you are looking for? Search for more explanations.