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- anonymous

on a map, three towns lie in a staight line. abbeyville is 35 miles from beanton. on the map this distance is 2 cm. the distance for abbeyvill to clarkton is 13 cm on the map. if beantown is between abbeyville and clarkton, how far in miles, is it from beantown to clarkton?

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- anonymous

- schrodinger

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- radar

There is probably many ways to set this problem up.
I am assuming you are into ratios and proportions.
From what was given the distance on the map from beantownto clarkton
is 13 cm - 2cm or 11 cm.
Then 2:35 :: 11:x With x being the distance in miles clarkton to beantown
35 times 11 = x times 2 (multiplying the means by the extremes)
2x=385
x=192.5 miles

- radar

Does this makes sense calissa7872? If not you could also look at it this way.
From the information that was given you found out that 1 cm = 17.5.
so after deducing you had 11 cm between clarkton and beantown, you could have
multiplied 11 times 17.5 and also got 192.5 miles.

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