anonymous
  • anonymous
one conveyor belt can move 1000 boxes in 7 minutes. another can move 1000 boxes in 11 minutes. if another conveyor belt is added and all three are used, the boxes are moved in 3 minutes. how long would it take the third conveyor belt alone to do the same job?
Mathematics
schrodinger
  • schrodinger
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
You are trying to find the speed of the third conveyor belt. So, the speed of the first one is: $$\frac{1000\textrm{ boxes}}{7\textrm{ min}} = \frac{1000}{7} \textrm{boxes/min}$$ Likewise for the second one: $$\frac{1000\textrm{ boxes}}{11\textrm{ min}} = \frac{1000}{11} \textrm{boxes/min}$$ And you know the total speed is: $$\frac{1000\textrm{ boxes}}{3\textrm{ min}} = \frac{1000}{3} \textrm{boxes/min}$$ The total speed has to be the sum of the three conveyor belt speeds, so you have: $$\textrm{(speed of conveyor belt 1)} + \textrm{(speed of conveyor belt 2)} + x = \textrm{total speed}$$ To find your answer, you therefore need to solve the equation: $$\frac{1000}{7} + \frac{1000}{11} + x = \frac{1000}{3}$$ The rest is left as an exercise for the reader. Also, your teacher is mean for giving your three prime numbers in this problem.

Looking for something else?

Not the answer you are looking for? Search for more explanations.