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anonymous
 5 years ago
7 over 5x squared 20x+20
plus
1 over 20x squared  80
anonymous
 5 years ago
7 over 5x squared 20x+20 plus 1 over 20x squared  80

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol, the question is not clear >_<

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.07 over 5x squared minus 20x plus 20 add to 1 over 20x squared minus 80

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i agree with sstarica because 7over 5x or 7over5 then an x ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{7}{5x^2}  20x + 20 + \frac{1}{20x^2}  80\]?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0______7_____ 5x squared 20x+20 added to 1 over 20x squared  80

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so is sstarica right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry for the confusion Ihavent quited figured out how to work this program yet

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{7}{5x^220x+20} + \frac{1}{20x80}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how do you get horizontal bars for the fractions with the maths editor

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{7}{5(x4)^2} + \frac{1}{20(x4)}\]\[\frac{7}{5(x^24x+4)} + \frac{1}{20(x4)}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0multiply top and bottom of second by x4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it's actually (x2)^2 :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nvm LOL, I wrote the wrong question

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeh something like that , im going to go to sleep soon

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no, wait, I wrote the right question >_<

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(x2)^2 ^_^" instead of (x4)^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its 1.40 in the morning where I am , I am too generous staying up this late to help ppls lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[= \frac{7(4)(x4) + (x2)(x2)}{20(x2)^2(x4)}\] \[= \frac{28x  112 +x^2  4x 4}{20(x2)^2(x4)}\] \[= \frac{x^2 + 24x 116}{20(x2)^2(x4)}\] hmm, there's something wrong

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0did you understand what I just did?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0not really i'm not very smart with algebra

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I factored, then put both fractions with the same denominator to have them in one :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0write down the steps on paper, and you'll figure out what I did ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait a min, there's a mistake in the last 2 steps, hold on dear ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm lost because under the 1 in 20x squared minues 80

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[= \frac{28x112+x24x+4}{20(x2)^2(x4)}\]< for the second line

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I factored, I pulled out 20 as a common factor and was left with (x4) use the distributive law to check ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[= \frac{x^2+24x108}{20(x2)^2(x4)}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry about the mess, but are you following now :)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think so, thank you so much

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0np ^_^, but there's still something fishy about it lol, I can't seem to factor the numerator

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0does the question want you to add only? or simplify?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm sure of the following steps I just made, but looks it can't be factored
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