7 over 5x squared -20x+20
plus
1 over 20x squared - 80

- anonymous

7 over 5x squared -20x+20
plus
1 over 20x squared - 80

- chestercat

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- anonymous

lol, the question is not clear >_<

- anonymous

7 over 5x squared minus 20x plus 20 add to 1 over 20x squared minus 80

- anonymous

i agree with sstarica
because 7over 5x or 7over5 then an x ?

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## More answers

- anonymous

\[\frac{7}{5x^2} - 20x + 20 + \frac{1}{20x^2} - 80\]?

- anonymous

______7_____
5x squared -20x+20 added to 1 over 20x squared - 80

- anonymous

so is sstarica right?

- anonymous

sorry for the confusion Ihavent quited figured out how to work this program yet

- anonymous

\[\frac{7}{5x^2-20x+20} + \frac{1}{20x-80}\]

- anonymous

yes

- anonymous

alright lol :)

- anonymous

how do you get horizontal bars for the fractions with the maths editor

- anonymous

frac{a}{b} <-- ^_^

- anonymous

\[\frac{7}{5(x-4)^2} + \frac{1}{20(x-4)}\]\[\frac{7}{5(x^2-4x+4)} + \frac{1}{20(x-4)}\]

- anonymous

wrong order
lol

- anonymous

lol, I noticed

- anonymous

multiply top and bottom of second by x-4

- anonymous

it's actually (x-2)^2 :)

- anonymous

nvm LOL, I wrote the wrong question

- anonymous

yeh something like that , im going to go to sleep soon

- anonymous

no, wait, I wrote the right question >_<

- anonymous

(x-2)^2 ^_^" instead of (x-4)^2

- anonymous

its 1.40 in the morning where I am , I am too generous staying up this late to help ppls lol

- anonymous

lol, go to bed

- anonymous

\[= \frac{7(4)(x-4) + (x-2)(x-2)}{20(x-2)^2(x-4)}\]
\[= \frac{28x - 112 +x^2 - 4x -4}{20(x-2)^2(x-4)}\]
\[= \frac{x^2 + 24x -116}{20(x-2)^2(x-4)}\]
hmm, there's something wrong

- anonymous

I'm not sure

- anonymous

did you understand what I just did?

- anonymous

not really i'm not very smart with algebra

- anonymous

I factored, then put both fractions with the same denominator to have them in one :)

- anonymous

write down the steps on paper, and you'll figure out what I did ^_^

- anonymous

wait a min, there's a mistake in the last 2 steps, hold on dear ^_^

- anonymous

I'm lost because under the 1 in 20x squared minues 80

- anonymous

\[= \frac{28x-112+x2-4x+4}{20(x-2)^2(x-4)}\]<-- for the second line

- anonymous

I factored, I pulled out 20 as a common factor and was left with (x-4) use the distributive law to check ^_^

- anonymous

\[= \frac{x^2+24x-108}{20(x-2)^2(x-4)}\]

- anonymous

sorry about the mess, but are you following now :)?

- anonymous

i think so, thank you so much

- anonymous

np ^_^, but there's still something fishy about it lol, I can't seem to factor the numerator

- anonymous

does the question want you to add only? or simplify?

- anonymous

simplify

- anonymous

hmm

- anonymous

I'm sure of the following steps I just made, but looks it can't be factored

- anonymous

thank you

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