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anonymous

  • 5 years ago

Solve the inequality (x/2) > (-8)/(x + 4) + 3 for domain

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  1. anonymous
    • 5 years ago
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    Multiply through with 2(x+4)

  2. anonymous
    • 5 years ago
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    Soooo x > ( -16/2x +8) + 6?

  3. anonymous
    • 5 years ago
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    You are way off. The first term should start out like this: \[(x(2)(x+2) \div 2)\] If you notice the 2s cancel.

  4. anonymous
    • 5 years ago
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    Im sorry im really confused as to whats going on...

  5. anonymous
    • 5 years ago
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    Im sorry im really confused as to whats going on...

  6. anonymous
    • 5 years ago
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    The terms are in the form of fractions. In order to make it simpler you can get rid of the fractions. In order to get rid of the fractions, you multiply each term by 2(x+4)

  7. anonymous
    • 5 years ago
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    Just to make sure were looking at the same thing, the original problem looks like this \[x \div2 > \left( \left( -8 \right)\div \left( x+4 \right) \right) + 3\]

  8. anonymous
    • 5 years ago
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    Yes pay attention to the terms in the bottom (denominator): 2 and (x + 4). You have to get rid of the fractions to make it easier to handle.

  9. anonymous
    • 5 years ago
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    sooo its \[x \times 2(x + 4) > -8 \times 2(x + 4) + 3\times 2(x + 4)\]

  10. anonymous
    • 5 years ago
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    You are seeing OK but you are not performing the operations. May be write it out on a piece of paper. You can not just make the bottom (denominator) disappear by magic. You have to cancel it out with something. You cross out the 2 at the bottom AND cross out the 2 on top. On the other side cross out the (x+4) on the bottom AND (x+4) on top. Your answer would be slightly different. But you are beginning to see it.

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