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anonymous
 5 years ago
Simplify log(base a)1log(base a)a^b
anonymous
 5 years ago
Simplify log(base a)1log(base a)a^b

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0log(1/(a^b)) => log(a^(b)) => blog(a) => b sing base is a we have b

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Remember that by definition, for any number x, $$\log_x 1= 0,$$ since any number to the zeroth power is 1. Also, remember that, by definition for any number x, $$\log_x x^b = b.$$ That's what a logarithm is. So combining those two: $$\log_a 1  \log_a a^b = 1  b$$ That's right, the a doesn't matter at all!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sorry, I that last equation was supposed to read: $$\log_a 1  \log_a a^b = b$$

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Rule #1 of posting corrections: your correction will itself contain a mistake. <goes away grumbling darkly/>

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanks, i couldnt put the equation thing. so the answer is just b??? that simple?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but you said logx1=0 so shoudltn it be 0b?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.00 is not a "simplification"; it is an overcomplication :)
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