anonymous
  • anonymous
Simplify log(base a)1-log(base a)a^b
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
log(1/(a^b)) => log(a^(-b)) => -blog(a) => -b sing base is a we have -b
anonymous
  • anonymous
Remember that by definition, for any number x, $$\log_x 1= 0,$$ since any number to the zeroth power is 1. Also, remember that, by definition for any number x, $$\log_x x^b = b.$$ That's what a logarithm is. So combining those two: $$\log_a 1 - \log_a a^b = 1 - b$$ That's right, the a doesn't matter at all!
anonymous
  • anonymous
Sorry, I that last equation was supposed to read: $$\log_a 1 - \log_a a^b = -b$$

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anonymous
  • anonymous
Rule #1 of posting corrections: your correction will itself contain a mistake.
anonymous
  • anonymous
thanks, i couldnt put the equation thing. so the answer is just -b??? that simple?
amistre64
  • amistre64
yes, -b
anonymous
  • anonymous
but you said logx1=0 so shoudltn it be 0-b?
amistre64
  • amistre64
0 is not a "simplification"; it is an overcomplication :)
amistre64
  • amistre64
0 -b = -b ; see :)
anonymous
  • anonymous
ok :) thanks

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