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anonymous

  • 5 years ago

sector qs: Charles has a slice of cake; its cross section is a sector of a circle. The radius is r cm and the sector angle is pi/6 radians. he wants to give half of the slice to Jan. He makes a cut across the sector show that when they have half the slice, a=r (sqrt pi/6)

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  1. anonymous
    • 5 years ago
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    I WANT CAKE <3

  2. amistre64
    • 5 years ago
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    a = area?

  3. amistre64
    • 5 years ago
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    if its just the area of the circle, then thats a pretty thin piece of cake...

  4. amistre64
    • 5 years ago
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    its hard to determine what "a" is supposed to represent; area, arc length, angle ???

  5. anonymous
    • 5 years ago
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    this is what it looks like and a is labelled

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  6. amistre64
    • 5 years ago
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    ok... is that "a" cm on the radius then?

  7. amistre64
    • 5 years ago
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    a = r * sqrt(pi/6) eh.... still not clicking anything useful in me head...srry...

  8. amistre64
    • 5 years ago
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    if it is exactly half the area of the sector; the the area of the whole is r^2(pi/6)/2

  9. amistre64
    • 5 years ago
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    divide that in half and we get (pi r^2)/24 as the area of each piece. area of a triangle can be found by: (side)(side)(sin(t))/2....which in this case is 2side sin(t)/2 = side(sin(t))

  10. amistre64
    • 5 years ago
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    a sin(pi/6) = (pi r^2)/24 a (1/2) (24) = pi r^2 12a/pi = r^2 a = pi r^2/12 really

  11. amistre64
    • 5 years ago
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    or is "cut in half" mean something else?

  12. anonymous
    • 5 years ago
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    cut in half is that line on the pic. and a cm is half

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