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anonymous

  • 5 years ago

Solve the inequality (x/2) > (-8)/(x + 4) + 3 for domain

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  1. amistre64
    • 5 years ago
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    is the "3" in the denominator??

  2. anonymous
    • 5 years ago
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    The 3 is added on after the fraction so I suppose its + 3/1

  3. amistre64
    • 5 years ago
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    x -8 -- > ----- + 3 2 x+4 get common denoms...

  4. amistre64
    • 5 years ago
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    (x^2 +4x) > -16 + 6x +24 (x^2 +4x) > 6x + 8 x^2 +4x -6x > 8 x^2 -2x >8 x^2 -2x -8 > 0

  5. amistre64
    • 5 years ago
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    (x-4)(x+2) >0 when x = -2 or 4; the equation = 0; so lets draw a number line: <.......-2...........4..........> - + + - - + --------------------- + - +

  6. amistre64
    • 5 years ago
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    this tells us that when: x = -2, everything to the left is (-) and to the right is (+) x = 4, everything to the left is (-) and to the right is (+) We multiply the signs together to get the bottom stuff; our answer is everything that is (+); becasue that is greater than zero. (-inf,-2) OR (4,inf)

  7. anonymous
    • 5 years ago
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    hmmm that doesnt appear to be one of the answers but ill double check the work

  8. amistre64
    • 5 years ago
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    try x= -2 (-2/2) > (-8)/(-2 + 4) + 3 -1 > -8/2 + 3 -1 > -4 + 3 -1> -1... -2 is one of the "options" there :)

  9. amistre64
    • 5 years ago
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    try x= 4 (4/2) > (-8)/(4 + 4) + 3 2 > -8/8 + 3 2 > -1 + 3 2> 2... 4 is the other "option" there :)

  10. amistre64
    • 5 years ago
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    we know zero is between them, so lets see if we include that or exclude that area... try x= 0 (0/2) > (-8)/(0 + 4) + 3 0 > -8/4 + 3 0 > -2 + 3 0> -1 is a false statement so the area that has "0" in it is thrown out; that only leaves: (-inf,-2) U (4,inf)

  11. anonymous
    • 5 years ago
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    These are the answers available: A. (- inf, -4) U (-2, 4) B. (- inf, -4) U [-2, 4] C. (-4, -2] U [4, inf) D. (- inf, -4] U [-2, 4) E. (-4, -2) U (4, inf)

  12. amistre64
    • 5 years ago
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    Check the problem, did you typo a sign?

  13. anonymous
    • 5 years ago
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    x -8 --- > ---- + 3 2 x+4

  14. amistre64
    • 5 years ago
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    i see an error on my part :) for starters 0 IS > -1, so zero is a solution

  15. amistre64
    • 5 years ago
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    never mind that comment, its my senility taking riit :)

  16. amistre64
    • 5 years ago
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    root... its like my fingers are having a stroke ....

  17. amistre64
    • 5 years ago
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    there is no "equal to" line in the equaiton, so it aint gonna have any [...] in it;

  18. amistre64
    • 5 years ago
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    I think it narrows down to "E" -6/2 = -3 -3 > -8 + 3 -3 > -5 is true, so -6 is a solution so "E" is wrong. You got something messed up in either the answers or the questions; because the 2 dont match up.... unless you can see an error in my calculations

  19. amistre64
    • 5 years ago
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    and -4 is not an option; becasue that zeros out the denom....

  20. anonymous
    • 5 years ago
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    I plugged it into my calculator and im trying to eye it from the graph

  21. amistre64
    • 5 years ago
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    no -4 and no 0 A. -------------- B. --------------- C. (-4, -2] U [4, inf) D. -------------- E. (-4, -2) U (4, inf)

  22. amistre64
    • 5 years ago
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    there is no "greater than or EQUAL TO" sign in it so no "[4" 4/2 > -8/8 +3 2> -1 +3 2>2 ...... bad statement A. -------------- B. --------------- C. ------------- D. -------------- E. (-4, -2) U (4, inf) test for "E"?

  23. amistre64
    • 5 years ago
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    x = -6 -6/2 = -8(-6+4) + 3 -3> -8/-2 + 3 -3 > 4+3 = 7...... -6 is a bad number and anything on that end... the answer is "E" then

  24. anonymous
    • 5 years ago
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    I plugged it into my calculator and im trying to eye it from the graph

  25. anonymous
    • 5 years ago
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    I keep retrying it but it keeps turning out wrong! grrr

  26. amistre64
    • 5 years ago
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    use a pencil and paper ;)

  27. anonymous
    • 5 years ago
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    I did, ive solved it 4 times now :/

  28. amistre64
    • 5 years ago
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    we know that -2 and 4 are boundaries; we know that zero is not an option; we know that {4 is not an option becasue there is no ">=" in the equation; that leaves "E" as the only possible shot. the only thing we need to determine is if it ends at -4 or not; so plug in a -6 and see if it hold :)

  29. amistre64
    • 5 years ago
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    -6 is bad value, so "E" is correct.

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