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anonymous

  • 5 years ago

Evaluate the Indefinite Integral 2u(u^2+1)^2 du

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  1. amistre64
    • 5 years ago
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    D(u^2 +1 ) = 2u

  2. anonymous
    • 5 years ago
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    Try using substitution and let x = u^2 + 1

  3. amistre64
    • 5 years ago
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    lol.......trig sub ;)

  4. anonymous
    • 5 years ago
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    not so much trig sub but regular substitution

  5. anonymous
    • 5 years ago
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    x = u^2 + 1 dx = 2u du \[\int\limits_{}^{}x^2dx = \frac{1}{3}x^3 = \frac{1}{3}(u^2 + 1)^3\]

  6. amistre64
    • 5 years ago
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    ...trig sub!!... its all I can do ;)

  7. anonymous
    • 5 years ago
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    amistre loves his trig subs

  8. amistre64
    • 5 years ago
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    trig sub tis; trig sub that; but the trig sub tshirt and ride the rides.....trig sub!!!!

  9. anonymous
    • 5 years ago
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    ROFLLL!!

  10. anonymous
    • 5 years ago
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    chiaroscuro - was that your final answer? It's actually a multiple choice question and I can't seem to figure out if I got the right answer or if it's "none of the above"

  11. anonymous
    • 5 years ago
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    1/3 (u^2 + 1)^3

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