find the four odd consecutive integers whose sum is 132.and find the product of the smallest and largest integer?

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find the four odd consecutive integers whose sum is 132.and find the product of the smallest and largest integer?

Mathematics
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Let x be the first one of the 4. That means that the second one is?
x+1
right?

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Not quite. x+1 would be the next integer, but not the next odd one. Each odd integer is how far away from the next odd integer?
could you please explain me this in detail?
Lets say that 3 is the first odd integer, What is the next odd integer after 3?
5
And 3 is how far from 5
1
5-3 = 1?
right
I'm pretty sure 5-3 = 2
right
So how far away from 5 is the next odd integer?
3
sorry 2
Right
So if x is the first odd integer in our series, then what are the other 4?
Err other 3 rather
X+3,X+5,X+7
what happen is this right?
Not quite. The distance between each one is 2. So the first one is x, the second is x+2, the third is x+4, and the fourth?
x+6
is this right?
please give a reply
Yes. Ok, so now we have the sum of these is 132.
ok cant we do this like firs intger as x and other integrs like x+1,x+2,x+3,x+4
No, because if x is 3, the x+1 would be 4 which is not the next odd integer.
We need them all to be odd, so we need to add 2 every time, not 1
ok thankyou
it helped me
Ok so now you have the equation x + x+2 + x+4 + x+6 = 132. Solve for x.

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