find the four odd consecutive integers whose sum is 132.and find the product of the smallest and largest integer?

- anonymous

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- anonymous

Let x be the first one of the 4. That means that the second one is?

- anonymous

x+1

- anonymous

right?

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- anonymous

Not quite. x+1 would be the next integer, but not the next odd one. Each odd integer is how far away from the next odd integer?

- anonymous

could you please explain me this in detail?

- anonymous

Lets say that 3 is the first odd integer, What is the next odd integer after 3?

- anonymous

5

- anonymous

And 3 is how far from 5

- anonymous

1

- anonymous

5-3 = 1?

- anonymous

right

- anonymous

I'm pretty sure 5-3 = 2

- anonymous

right

- anonymous

So how far away from 5 is the next odd integer?

- anonymous

3

- anonymous

sorry 2

- anonymous

Right

- anonymous

So if x is the first odd integer in our series, then what are the other 4?

- anonymous

Err other 3 rather

- anonymous

X+3,X+5,X+7

- anonymous

what happen is this right?

- anonymous

Not quite. The distance between each one is 2.
So the first one is x, the second is x+2, the third is x+4, and the fourth?

- anonymous

x+6

- anonymous

is this right?

- anonymous

please give a reply

- anonymous

Yes. Ok, so now we have the sum of these is 132.

- anonymous

ok cant we do this like firs intger as x and other integrs like x+1,x+2,x+3,x+4

- anonymous

No, because if x is 3, the x+1 would be 4 which is not the next odd integer.

- anonymous

We need them all to be odd, so we need to add 2 every time, not 1

- anonymous

ok thankyou

- anonymous

it helped me

- anonymous

Ok so now you have the equation
x + x+2 + x+4 + x+6 = 132. Solve for x.

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