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anonymous

  • 5 years ago

find the four odd consecutive integers whose sum is 132.and find the product of the smallest and largest integer?

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  1. anonymous
    • 5 years ago
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    Let x be the first one of the 4. That means that the second one is?

  2. anonymous
    • 5 years ago
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    x+1

  3. anonymous
    • 5 years ago
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    right?

  4. anonymous
    • 5 years ago
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    Not quite. x+1 would be the next integer, but not the next odd one. Each odd integer is how far away from the next odd integer?

  5. anonymous
    • 5 years ago
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    could you please explain me this in detail?

  6. anonymous
    • 5 years ago
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    Lets say that 3 is the first odd integer, What is the next odd integer after 3?

  7. anonymous
    • 5 years ago
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    5

  8. anonymous
    • 5 years ago
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    And 3 is how far from 5

  9. anonymous
    • 5 years ago
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    1

  10. anonymous
    • 5 years ago
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    5-3 = 1?

  11. anonymous
    • 5 years ago
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    right

  12. anonymous
    • 5 years ago
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    I'm pretty sure 5-3 = 2

  13. anonymous
    • 5 years ago
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    right

  14. anonymous
    • 5 years ago
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    So how far away from 5 is the next odd integer?

  15. anonymous
    • 5 years ago
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    3

  16. anonymous
    • 5 years ago
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    sorry 2

  17. anonymous
    • 5 years ago
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    Right

  18. anonymous
    • 5 years ago
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    So if x is the first odd integer in our series, then what are the other 4?

  19. anonymous
    • 5 years ago
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    Err other 3 rather

  20. anonymous
    • 5 years ago
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    X+3,X+5,X+7

  21. anonymous
    • 5 years ago
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    what happen is this right?

  22. anonymous
    • 5 years ago
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    Not quite. The distance between each one is 2. So the first one is x, the second is x+2, the third is x+4, and the fourth?

  23. anonymous
    • 5 years ago
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    x+6

  24. anonymous
    • 5 years ago
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    is this right?

  25. anonymous
    • 5 years ago
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    please give a reply

  26. anonymous
    • 5 years ago
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    Yes. Ok, so now we have the sum of these is 132.

  27. anonymous
    • 5 years ago
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    ok cant we do this like firs intger as x and other integrs like x+1,x+2,x+3,x+4

  28. anonymous
    • 5 years ago
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    No, because if x is 3, the x+1 would be 4 which is not the next odd integer.

  29. anonymous
    • 5 years ago
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    We need them all to be odd, so we need to add 2 every time, not 1

  30. anonymous
    • 5 years ago
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    ok thankyou

  31. anonymous
    • 5 years ago
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    it helped me

  32. anonymous
    • 5 years ago
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    Ok so now you have the equation x + x+2 + x+4 + x+6 = 132. Solve for x.

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