## anonymous 5 years ago Solve each problem by using the quadratic formula. Write solutions in simplest radical form. 2x^2 + 2x- 1 = 0

1. anonymous

so ax^2 + bx + c = 0

2. anonymous

$(-b \pm \sqrt{b^2 - 4 a c}) /2a$

3. anonymous

just plug in the values your equation is 2x^2 + 2x - 1 = 0 ax^2 + bx + c = 0

4. anonymous

tell me what a = , b = , and c =

5. anonymous

are they a=2 b=2 c= -1 ?

6. anonymous

perfect now plug them into the quadratic equaiton

7. anonymous

and you must rememeber the pm

8. anonymous

pm -> plus and minus

9. anonymous

because you will have two solutions one for a positive square root, and one for a negative square root

10. anonymous

$-2\pm \sqrt{12} /4$ this is what im getting so far am i on the right track

11. anonymous

yeah. see that plus and minus you have to look at it like this -2 + sqrt(12)/4 and -2 - sqrt(12)/4

12. anonymous

so you will get two answers

13. anonymous

would the first answer be 1 and the second answer be -2

14. anonymous

you will get -1 +- sqrt(3)/2

15. anonymous

i have to go

16. anonymous

you will get -1 +- sqrt(3)/2