Solve each problem by using the quadratic formula. Write solutions in simplest radical form. 2x^2 + 2x- 1 = 0

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Solve each problem by using the quadratic formula. Write solutions in simplest radical form. 2x^2 + 2x- 1 = 0

Mathematics
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so ax^2 + bx + c = 0
\[(-b \pm \sqrt{b^2 - 4 a c}) /2a\]
just plug in the values your equation is 2x^2 + 2x - 1 = 0 ax^2 + bx + c = 0

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tell me what a = , b = , and c =
are they a=2 b=2 c= -1 ?
perfect now plug them into the quadratic equaiton
and you must rememeber the pm
pm -> plus and minus
because you will have two solutions one for a positive square root, and one for a negative square root
\[-2\pm \sqrt{12} /4\] this is what im getting so far am i on the right track
yeah. see that plus and minus you have to look at it like this -2 + sqrt(12)/4 and -2 - sqrt(12)/4
so you will get two answers
would the first answer be 1 and the second answer be -2
you will get -1 +- sqrt(3)/2
i have to go
you will get -1 +- sqrt(3)/2

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