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anonymous
 5 years ago
Use USubstitution to evaluate the Integral:
anonymous
 5 years ago
Use USubstitution to evaluate the Integral:

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0u=(x^{4} + 3x^{2} +5)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{?}^{?} (4x^{3} +6x) \cos (x^{4} + 3x^{2} + 5 ) dx\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I have to integrate that above this post with the U given in the first post. Please confirm my answer if you can!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Actually I couldn't get an answer  please helpz!!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0= sin ( u ) = sin ( x^4 + 3x^3 + 5) + C

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry the second x should be squared ( 3x^2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0because u = x^4 + 3x^3 + 5 ==> du/dx = 4x^3 + 6x solve for dx and plug the equation for dx into the integral

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if you write that out you will notice you have 4x^3 + 6x in the numerator and denominator and that equals 1. but you are still multiplying by du. because you had to solve for dx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you get \[\int\limits_{?}^{?}\cos u du\] = sin u then just plug u back into the sing

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0taking a step back when you solve for dx you should get dx = du / (4x^3 + 6x) plug that into the integral. you are integrating du with respect to u

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sin(x^{4} + 3x^{2} + 5) + c \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0awesome!! thank you so much!!
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