anonymous
  • anonymous
What is the volume of the solid of revolution generated by revolving the area bounded by y = 2, y = x+3 and x = 4 around the x-axis
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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amistre64
  • amistre64
ahhh volume of solids :) nice
amistre64
  • amistre64
isnt that just a cone?
anonymous
  • anonymous
Lol - up for helping me out one more time?

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More answers

amistre64
  • amistre64
spin this right?
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amistre64
  • amistre64
it amounts to a cylinder and a cone :)
anonymous
  • anonymous
Yes, that's the same sketch I made
anonymous
  • anonymous
Lol
amistre64
  • amistre64
y = 2 when x = -1; -1 to 4 is 5 units; area of the left part is 5(pi) 2^2
amistre64
  • amistre64
20 pi is the area of the "cylindar"; now add the cone...
amistre64
  • amistre64
we have a base area of pi 2^2 = 4pi; and a height from -1 to -3 = 2
amistre64
  • amistre64
4pi(2) ----- = 8pi/3 add the other 3 8pi + 60pi --------- = 68pi/3 3
amistre64
  • amistre64
thats my guess :) cone plus cylinder = total;
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myininaya
  • myininaya
this might be wrong but I have to leave
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amistre64
  • amistre64
that might be right :)
anonymous
  • anonymous
hmm -
amistre64
  • amistre64
we can solve both ways ;)
myininaya
  • myininaya
you guys have fun i have a date lol
amistre64
  • amistre64
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anonymous
  • anonymous
hmm - i'm not sure if 68pi/3 is right
amistre64
  • amistre64
we move everything to the right by 1 to get bounbes from 0 to 5; then rotate the triangle in a torus
anonymous
  • anonymous
It was a multiple choice question from the book - but no answer in the back to confirm
amistre64
  • amistre64
\[\pi \int\limits_{0}^{5} [f(x)]^2 dx\]
amistre64
  • amistre64
y=x+3 when moved to the right by 1 becomes: y+1 = x+3 y = x+2 integrate (x+2)^2
amistre64
  • amistre64
(x+2)^3 ------- = F(x); play with the 5 and we get... 343pi/3 3
anonymous
  • anonymous
the numerator seems to be off - it's either 14 pi, 275 pi or 140 pi
anonymous
  • anonymous
I can't seem to get any of those numbers on accident either!
amistre64
  • amistre64
lets see if I integrated it forrectly :) u = x+2; du = dx [S] u^2 du -> (u^3)/3 = (x+2)^3/3 thats right....
amistre64
  • amistre64
its from 0 to 5 so..... thats where I misssed it lol pi(343-8)/3
amistre64
  • amistre64
i assumed 0 was just 0
amistre64
  • amistre64
we have to subtract something; the area of the cylindar beneath it.....
amistre64
  • amistre64
we made a solid and forgot to ...by we I mean me lol..... forgot to take away the solid formed beneath it
anonymous
  • anonymous
lol
amistre64
  • amistre64
subtract another 20pi
amistre64
  • amistre64
pi(343-68)/3 275pi/3
anonymous
  • anonymous
Great! Glad we (I mean you) could figure it out and explain it to me! Lol
amistre64
  • amistre64
lol.... i took the whole thing and forgot to cut out the center of the doughnot.... that was my error the first go araound
anonymous
  • anonymous
No worries!! I'm glad you could figure it out!
anonymous
  • anonymous
I appreciate the help very much! I may post a few more if you're still around!
amistre64
  • amistre64
this is the visual lol
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amistre64
  • amistre64
i gotsta take a macroeconomics final so good luck ;)
anonymous
  • anonymous
Ahh! Haha
anonymous
  • anonymous
Good luck!

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