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anonymous

  • 5 years ago

What is the volume of the solid of revolution generated by revolving the area bounded by y = 2, y = x+3 and x = 4 around the x-axis

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  1. amistre64
    • 5 years ago
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    ahhh volume of solids :) nice

  2. amistre64
    • 5 years ago
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    isnt that just a cone?

  3. anonymous
    • 5 years ago
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    Lol - up for helping me out one more time?

  4. amistre64
    • 5 years ago
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    spin this right?

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  5. amistre64
    • 5 years ago
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    it amounts to a cylinder and a cone :)

  6. anonymous
    • 5 years ago
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    Yes, that's the same sketch I made

  7. anonymous
    • 5 years ago
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    Lol

  8. amistre64
    • 5 years ago
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    y = 2 when x = -1; -1 to 4 is 5 units; area of the left part is 5(pi) 2^2

  9. amistre64
    • 5 years ago
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    20 pi is the area of the "cylindar"; now add the cone...

  10. amistre64
    • 5 years ago
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    we have a base area of pi 2^2 = 4pi; and a height from -1 to -3 = 2

  11. amistre64
    • 5 years ago
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    4pi(2) ----- = 8pi/3 add the other 3 8pi + 60pi --------- = 68pi/3 3

  12. amistre64
    • 5 years ago
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    thats my guess :) cone plus cylinder = total;

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  13. myininaya
    • 5 years ago
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    this might be wrong but I have to leave

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  14. amistre64
    • 5 years ago
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    that might be right :)

  15. anonymous
    • 5 years ago
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    hmm -

  16. amistre64
    • 5 years ago
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    we can solve both ways ;)

  17. myininaya
    • 5 years ago
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    you guys have fun i have a date lol

  18. amistre64
    • 5 years ago
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  19. anonymous
    • 5 years ago
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    hmm - i'm not sure if 68pi/3 is right

  20. amistre64
    • 5 years ago
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    we move everything to the right by 1 to get bounbes from 0 to 5; then rotate the triangle in a torus

  21. anonymous
    • 5 years ago
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    It was a multiple choice question from the book - but no answer in the back to confirm

  22. amistre64
    • 5 years ago
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    \[\pi \int\limits_{0}^{5} [f(x)]^2 dx\]

  23. amistre64
    • 5 years ago
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    y=x+3 when moved to the right by 1 becomes: y+1 = x+3 y = x+2 integrate (x+2)^2

  24. amistre64
    • 5 years ago
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    (x+2)^3 ------- = F(x); play with the 5 and we get... 343pi/3 3

  25. anonymous
    • 5 years ago
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    the numerator seems to be off - it's either 14 pi, 275 pi or 140 pi

  26. anonymous
    • 5 years ago
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    I can't seem to get any of those numbers on accident either!

  27. amistre64
    • 5 years ago
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    lets see if I integrated it forrectly :) u = x+2; du = dx [S] u^2 du -> (u^3)/3 = (x+2)^3/3 thats right....

  28. amistre64
    • 5 years ago
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    its from 0 to 5 so..... thats where I misssed it lol pi(343-8)/3

  29. amistre64
    • 5 years ago
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    i assumed 0 was just 0

  30. amistre64
    • 5 years ago
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    we have to subtract something; the area of the cylindar beneath it.....

  31. amistre64
    • 5 years ago
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    we made a solid and forgot to ...by we I mean me lol..... forgot to take away the solid formed beneath it

  32. anonymous
    • 5 years ago
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    lol

  33. amistre64
    • 5 years ago
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    subtract another 20pi

  34. amistre64
    • 5 years ago
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    pi(343-68)/3 275pi/3

  35. anonymous
    • 5 years ago
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    Great! Glad we (I mean you) could figure it out and explain it to me! Lol

  36. amistre64
    • 5 years ago
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    lol.... i took the whole thing and forgot to cut out the center of the doughnot.... that was my error the first go araound

  37. anonymous
    • 5 years ago
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    No worries!! I'm glad you could figure it out!

  38. anonymous
    • 5 years ago
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    I appreciate the help very much! I may post a few more if you're still around!

  39. amistre64
    • 5 years ago
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    this is the visual lol

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  40. amistre64
    • 5 years ago
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    i gotsta take a macroeconomics final so good luck ;)

  41. anonymous
    • 5 years ago
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    Ahh! Haha

  42. anonymous
    • 5 years ago
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    Good luck!

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