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anonymous

  • 5 years ago

whats the integral of (e^x-2) dx?

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  1. anonymous
    • 5 years ago
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    So what is the derivative of e^x-2? Just go backwards. What would you take the derivative to get e^x-2? Also, quick question. Do you mean e^(x-2) or e^(x) -2? Both are completely different.

  2. anonymous
    • 5 years ago
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    i meant e^(x) -2

  3. anonymous
    • 5 years ago
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    e^2x?

  4. anonymous
    • 5 years ago
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    what no

  5. anonymous
    • 5 years ago
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    nevermind is it, e^x -2x?

  6. anonymous
    • 5 years ago
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    So are you saying that the equation is \[e^x -2x\] then?

  7. anonymous
    • 5 years ago
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    yeah

  8. sgadi
    • 5 years ago
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    \[\int {(e^x-2)dx}=e^x-2x+c\] where c is constant.

  9. anonymous
    • 5 years ago
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    that seems too simply...

  10. anonymous
    • 5 years ago
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    thanks for the help

  11. anonymous
    • 5 years ago
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    Oh sorry, I misunderstood what you meant when you said "nevermind is it, e^x -2x?" I thought that was what you were taking the integral of.

  12. anonymous
    • 5 years ago
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    its fine, i worded it wrong so no worries

  13. anonymous
    • 5 years ago
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    i've just spent an hour integrating using substitution so when i got an easy problem i got really confused...

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