anonymous
  • anonymous
whats the integral of (e^x-2) dx?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
So what is the derivative of e^x-2? Just go backwards. What would you take the derivative to get e^x-2? Also, quick question. Do you mean e^(x-2) or e^(x) -2? Both are completely different.
anonymous
  • anonymous
i meant e^(x) -2
anonymous
  • anonymous
e^2x?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
what no
anonymous
  • anonymous
nevermind is it, e^x -2x?
anonymous
  • anonymous
So are you saying that the equation is \[e^x -2x\] then?
anonymous
  • anonymous
yeah
sgadi
  • sgadi
\[\int {(e^x-2)dx}=e^x-2x+c\] where c is constant.
anonymous
  • anonymous
that seems too simply...
anonymous
  • anonymous
thanks for the help
anonymous
  • anonymous
Oh sorry, I misunderstood what you meant when you said "nevermind is it, e^x -2x?" I thought that was what you were taking the integral of.
anonymous
  • anonymous
its fine, i worded it wrong so no worries
anonymous
  • anonymous
i've just spent an hour integrating using substitution so when i got an easy problem i got really confused...

Looking for something else?

Not the answer you are looking for? Search for more explanations.