A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
the two lines x=ay+b, z= cy+d and x=a'y+b', z=c'y+d' are perpendicular to each other, if:
(a) aa'+cc'=1
(b) (a/a') + (c/c') =1
(c) (a/a')+(c/c')=1
(d) aa'+cc'=1
anonymous
 5 years ago
the two lines x=ay+b, z= cy+d and x=a'y+b', z=c'y+d' are perpendicular to each other, if: (a) aa'+cc'=1 (b) (a/a') + (c/c') =1 (c) (a/a')+(c/c')=1 (d) aa'+cc'=1

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the answer would be d since we can rewrite the first two lines as y=(xb)/a y=(zd)/c therefore ((xb)/a)= ((zd)/c) which gives us <x,1,c> similar we write the second two lines is that for giving us <x',1,z'> and we know if they are perpendicular the dot product gives us 0 thus xx'+1+zz'=0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok how did you get <x,1,c>??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i mixed up my signs halfway through it should be <a,1,c> and <a',1,c'> and aa'+1+cc'=0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohk that works.. thanx bro!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.