anonymous
  • anonymous
First one to answer i will give you a medal :) I z+3 I<=7 A.)z<=-10 or z=>4 B.)-104 D.)-10<=z<=4
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
20
anonymous
  • anonymous
20 what?
anonymous
  • anonymous
is the answer

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
I answered this already your answer is d
anonymous
  • anonymous
d
anonymous
  • anonymous
I z+3 I<=7 z+3<=7 subtract 3 from both sides z<=4
anonymous
  • anonymous
okay thanks
anonymous
  • anonymous
D
anonymous
  • anonymous
With that you can see it eliminates answers A-C so your final answer is D
anonymous
  • anonymous
wait what about this one?
anonymous
  • anonymous
SO DO I GET A MEDAL
anonymous
  • anonymous
you put 20 that wasnt a chocie
anonymous
  • anonymous
what about what one?
anonymous
  • anonymous
i said D.
anonymous
  • anonymous
okay i will give you one lmao
anonymous
  • anonymous
ok thanks
anonymous
  • anonymous
I c-6 I<=6
anonymous
  • anonymous
0<=C<=12
anonymous
  • anonymous
A.)c<=0 or c=>12 B.)012
anonymous
  • anonymous
c
anonymous
  • anonymous
You sure lol
anonymous
  • anonymous
yep
anonymous
  • anonymous
thanks :)
anonymous
  • anonymous
No problem any time:)
anonymous
  • anonymous
do you know how to tell if a equation is a function?
anonymous
  • anonymous
Uhm idk I could try I kind of remember What does the problem look like

Looking for something else?

Not the answer you are looking for? Search for more explanations.