anonymous
  • anonymous
What it says is: Determine the x-coordinates of the points of inflection for the graph of f(x). so I took the derivative of f(x)=9e and I got 0, how am I supposed to get a point of inflection from this?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
wait, i forgot to say something, I know that the point of inflection is the derivative of the function twice, and that is what 9e is, I had already taken the derivative once. :)
anonymous
  • anonymous
For inflection points you want to see when the curvature changes. That means that the second derivative changes sign.
anonymous
  • anonymous
Yep, but there is no x to set equal to x, sooo what do I do?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
x=0, sorry typoo
anonymous
  • anonymous
What was the original function
anonymous
  • anonymous
f(x)=3xe^(-x^2)
anonymous
  • anonymous
And you got 9e when you took the derivative?
anonymous
  • anonymous
Yep
anonymous
  • anonymous
That's unpossible
anonymous
  • anonymous
omg. omg. I realized what i did wrong. thank you
anonymous
  • anonymous
the i plugged in 1 for x for some odd, odd, odd reason.
anonymous
  • anonymous
If the derivative were 9e, then I should be able to integrate 9e and get back to the original function plus a constant. But the integral of 9e is 9ex
anonymous
  • anonymous
which is not the function
anonymous
  • anonymous
lol exactly. :) ha thank you!
anonymous
  • anonymous
=)

Looking for something else?

Not the answer you are looking for? Search for more explanations.