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anonymous

  • 5 years ago

What it says is: Determine the x-coordinates of the points of inflection for the graph of f(x). so I took the derivative of f(x)=9e and I got 0, how am I supposed to get a point of inflection from this?

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  1. anonymous
    • 5 years ago
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    wait, i forgot to say something, I know that the point of inflection is the derivative of the function twice, and that is what 9e is, I had already taken the derivative once. :)

  2. anonymous
    • 5 years ago
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    For inflection points you want to see when the curvature changes. That means that the second derivative changes sign.

  3. anonymous
    • 5 years ago
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    Yep, but there is no x to set equal to x, sooo what do I do?

  4. anonymous
    • 5 years ago
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    x=0, sorry typoo

  5. anonymous
    • 5 years ago
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    What was the original function

  6. anonymous
    • 5 years ago
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    f(x)=3xe^(-x^2)

  7. anonymous
    • 5 years ago
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    And you got 9e when you took the derivative?

  8. anonymous
    • 5 years ago
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    Yep

  9. anonymous
    • 5 years ago
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    That's unpossible

  10. anonymous
    • 5 years ago
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    omg. omg. I realized what i did wrong. thank you

  11. anonymous
    • 5 years ago
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    the i plugged in 1 for x for some odd, odd, odd reason.

  12. anonymous
    • 5 years ago
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    If the derivative were 9e, then I should be able to integrate 9e and get back to the original function plus a constant. But the integral of 9e is 9ex

  13. anonymous
    • 5 years ago
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    which is not the function

  14. anonymous
    • 5 years ago
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    lol exactly. :) ha thank you!

  15. anonymous
    • 5 years ago
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    =)

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spraguer (Moderator)
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