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anonymous

  • 5 years ago

I do not get slope

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  1. anonymous
    • 5 years ago
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    sorry

  2. anonymous
    • 5 years ago
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    Slope just tells you how much your output changes as your input changes.

  3. anonymous
    • 5 years ago
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    So if you have a slope of 2/3. That means each time your input changes by 3, your output changes by 2.

  4. anonymous
    • 5 years ago
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    oh ok

  5. anonymous
    • 5 years ago
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    can you help me with a problem ?

  6. anonymous
    • 5 years ago
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    sure

  7. anonymous
    • 5 years ago
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    \[4x ^{2}-3x+12-2x ^{2}+7x+16=\]

  8. anonymous
    • 5 years ago
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    This isn't really slope related. You just need to combine your 'like' terms.

  9. anonymous
    • 5 years ago
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    You have four \(x^2\)'s and you're taking away two \(x^2\)'s. How many \(x^2\)'s will be left?

  10. anonymous
    • 5 years ago
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    You have 7x's and you're taking away 3x's

  11. anonymous
    • 5 years ago
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    2x^(2)? and 4x^{2}?

  12. anonymous
    • 5 years ago
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    2\(x^2\) and 4x, and 16 and 12

  13. anonymous
    • 5 years ago
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    what's 16 and 12?

  14. anonymous
    • 5 years ago
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    28

  15. anonymous
    • 5 years ago
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    Ok so what's your answer?

  16. anonymous
    • 5 years ago
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    haha wait so my answer is \[2x ^{2}+4x+28\] ?

  17. anonymous
    • 5 years ago
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    yep

  18. anonymous
    • 5 years ago
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    ohh! wow so how do i show the work lol.. but thankss !

  19. anonymous
    • 5 years ago
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    Just move the things around. \[4x ^{2}-3x+12-2x ^{2}+7x+16\] \[= 4x^2 - 2x^2 + 7x -3x +12 + 16\] \[= 2x^2 + 4x + 28\]

  20. anonymous
    • 5 years ago
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    thankss so much

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