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anonymous
 5 years ago
what is the area of the triangle bounded by the lines: x=1, y=x1, y=3x
anonymous
 5 years ago
what is the area of the triangle bounded by the lines: x=1, y=x1, y=3x

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Some thing doesn't seem right. Check and write question word for word. Why is there two y's?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0All the info is correctly listed. I'm still stumped on it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What is the area of the triangle bounded by the lines x = 1, y = x − 1, and y = 3 − x ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OK, I get it. These are graphs of lines, not actual measurements.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes  they form a triangle when graphed. I need to find the area of that triangle.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You can graph it and get their measurements. Or you can use algebra, for example \[x1=3x\]Solve for x. That is one point of intersection. Depends on if you are a visual person, draw graph, if you are a logical thinker and algebra lover, do it by algebra.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so would the answer be 2? do I stop there?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0why just those 2 only?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the 3rd one really bumped me off the train lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No that is just one point of the triangle, x=2, punch that in the other triangle y=1. One corner of the triangle is at the point (2,1)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Alright, I worked it out and got (4) for the area of the triangle bounded by the lines

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0were you able to work up a quick answer to compare?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I haven't done it but if you tell me what you did, I can check.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I found the other 2 corners of the triangle and added/subtracted them together and got (4).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't know exactly what you did. You would have to give more detail. But to go that route you would have to know the (x,y) point of each intersection, use distance formula to compute distance then, area formula half base times height.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think I mixed up what I"m supposed to do

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I found all the points  where do I go from there exactly? I appreciate the help.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This is a simple enough graph that you could plot by hand to get the distances.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I just graphed it  just by looking at it, I see the area being a 1x1 box

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That is your first clue that you did something wrong. A triangle is a triangle, a box is a box. Take each y line, write down some values x=0, y= etc, and the line that says x=1 is just a straight line joining the two others.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I did that  I cut the triangle in half and made a box and just counted the units

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0My points for the triangle are: (1,1)  (2,1)  (1,2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0don't mind the "", I Just used those to space them out

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0May be you are right, I am just not familiar with your method. Area of a triangle can be found by half base times height http://mathcentral.uregina.ca/QQ/database/QQ.09.02/dean1.html

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Can we conclude that 1 is the answer?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So what course are you working so I can understand what level of math you are or else I might say thing you might not understand.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Don't get hang up on any one question, write the number down and go in to your teacher's office hours. You have a good work ethic. Keep it up. But you have to put in a lot of work because you are not asking calculus questions. Don't get discouraged. 'Keep working,' that's what my tutor says at the end of each session.
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