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anonymous

  • 5 years ago

what is the area of the triangle bounded by the lines: x=1, y=x-1, y=3-x

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  1. anonymous
    • 5 years ago
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    Some thing doesn't seem right. Check and write question word for word. Why is there two y's?

  2. anonymous
    • 5 years ago
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    All the info is correctly listed. I'm still stumped on it.

  3. anonymous
    • 5 years ago
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    What is the area of the triangle bounded by the lines x = 1, y = x − 1, and y = 3 − x ?

  4. anonymous
    • 5 years ago
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    OK, I get it. These are graphs of lines, not actual measurements.

  5. anonymous
    • 5 years ago
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    Yes - they form a triangle when graphed. I need to find the area of that triangle.

  6. anonymous
    • 5 years ago
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    You can graph it and get their measurements. Or you can use algebra, for example \[x-1=3-x\]Solve for x. That is one point of intersection. Depends on if you are a visual person, draw graph, if you are a logical thinker and algebra lover, do it by algebra.

  7. anonymous
    • 5 years ago
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    so would the answer be 2? do I stop there?

  8. anonymous
    • 5 years ago
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    why just those 2 only?

  9. anonymous
    • 5 years ago
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    the 3rd one really bumped me off the train lol

  10. anonymous
    • 5 years ago
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    No that is just one point of the triangle, x=2, punch that in the other triangle y=1. One corner of the triangle is at the point (2,1)

  11. anonymous
    • 5 years ago
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    Alright, I worked it out and got (4) for the area of the triangle bounded by the lines

  12. anonymous
    • 5 years ago
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    were you able to work up a quick answer to compare?

  13. anonymous
    • 5 years ago
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    I haven't done it but if you tell me what you did, I can check.

  14. anonymous
    • 5 years ago
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    I found the other 2 corners of the triangle and added/subtracted them together and got (4).

  15. anonymous
    • 5 years ago
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    I don't know exactly what you did. You would have to give more detail. But to go that route you would have to know the (x,y) point of each intersection, use distance formula to compute distance then, area formula half base times height.

  16. anonymous
    • 5 years ago
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    I think I mixed up what I"m supposed to do

  17. anonymous
    • 5 years ago
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    I found all the points - where do I go from there exactly? I appreciate the help.

  18. anonymous
    • 5 years ago
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    This is a simple enough graph that you could plot by hand to get the distances.

  19. anonymous
    • 5 years ago
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    I just graphed it - just by looking at it, I see the area being a 1x1 box

  20. anonymous
    • 5 years ago
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    well 2 triangles

  21. anonymous
    • 5 years ago
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    so the area is = 1

  22. anonymous
    • 5 years ago
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    That is your first clue that you did something wrong. A triangle is a triangle, a box is a box. Take each y line, write down some values x=0, y= etc, and the line that says x=1 is just a straight line joining the two others.

  23. anonymous
    • 5 years ago
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    I did that - I cut the triangle in half and made a box and just counted the units

  24. anonymous
    • 5 years ago
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    My points for the triangle are: (1,1) - (2,1) - (1,2)

  25. anonymous
    • 5 years ago
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    don't mind the "-", I Just used those to space them out

  26. anonymous
    • 5 years ago
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    May be you are right, I am just not familiar with your method. Area of a triangle can be found by half base times height http://mathcentral.uregina.ca/QQ/database/QQ.09.02/dean1.html

  27. anonymous
    • 5 years ago
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    (1/2)(2) x (1) = 1

  28. anonymous
    • 5 years ago
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    Can we conclude that 1 is the answer?

  29. anonymous
    • 5 years ago
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    So what course are you working so I can understand what level of math you are or else I might say thing you might not understand.

  30. anonymous
    • 5 years ago
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    Calc

  31. anonymous
    • 5 years ago
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    Don't get hang up on any one question, write the number down and go in to your teacher's office hours. You have a good work ethic. Keep it up. But you have to put in a lot of work because you are not asking calculus questions. Don't get discouraged. 'Keep working,' that's what my tutor says at the end of each session.

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