what is the area of the triangle bounded by the lines: x=1, y=x-1, y=3-x

- anonymous

what is the area of the triangle bounded by the lines: x=1, y=x-1, y=3-x

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- anonymous

Some thing doesn't seem right. Check and write question word for word. Why is there two y's?

- anonymous

All the info is correctly listed. I'm still stumped on it.

- anonymous

What is the area of the triangle bounded by the lines x = 1, y = x − 1, and y = 3 − x ?

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## More answers

- anonymous

OK, I get it. These are graphs of lines, not actual measurements.

- anonymous

Yes - they form a triangle when graphed. I need to find the area of that triangle.

- anonymous

You can graph it and get their measurements. Or you can use algebra, for example
\[x-1=3-x\]Solve for x. That is one point of intersection. Depends on if you are a visual person, draw graph, if you are a logical thinker and algebra lover, do it by algebra.

- anonymous

so would the answer be 2? do I stop there?

- anonymous

why just those 2 only?

- anonymous

the 3rd one really bumped me off the train lol

- anonymous

No that is just one point of the triangle, x=2, punch that in the other triangle y=1. One corner of the triangle is at the point (2,1)

- anonymous

Alright, I worked it out and got (4) for the area of the triangle bounded by the lines

- anonymous

were you able to work up a quick answer to compare?

- anonymous

I haven't done it but if you tell me what you did, I can check.

- anonymous

I found the other 2 corners of the triangle and added/subtracted them together and got (4).

- anonymous

I don't know exactly what you did. You would have to give more detail. But to go that route you would have to know the (x,y) point of each intersection, use distance formula to compute distance then, area formula half base times height.

- anonymous

I think I mixed up what I"m supposed to do

- anonymous

I found all the points - where do I go from there exactly? I appreciate the help.

- anonymous

This is a simple enough graph that you could plot by hand to get the distances.

- anonymous

I just graphed it - just by looking at it, I see the area being a 1x1 box

- anonymous

well 2 triangles

- anonymous

so the area is = 1

- anonymous

That is your first clue that you did something wrong. A triangle is a triangle, a box is a box. Take each y line, write down some values x=0, y= etc, and the line that says x=1 is just a straight line joining the two others.

- anonymous

I did that - I cut the triangle in half and made a box and just counted the units

- anonymous

My points for the triangle are: (1,1) - (2,1) - (1,2)

- anonymous

don't mind the "-", I Just used those to space them out

- anonymous

May be you are right, I am just not familiar with your method. Area of a triangle can be found by half base times height http://mathcentral.uregina.ca/QQ/database/QQ.09.02/dean1.html

- anonymous

(1/2)(2) x (1) = 1

- anonymous

Can we conclude that 1 is the answer?

- anonymous

So what course are you working so I can understand what level of math you are or else I might say thing you might not understand.

- anonymous

Calc

- anonymous

Don't get hang up on any one question, write the number down and go in to your teacher's office hours. You have a good work ethic. Keep it up. But you have to put in a lot of work because you are not asking calculus questions. Don't get discouraged. 'Keep working,' that's what my tutor says at the end of each session.

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