anonymous
  • anonymous
Solve for x: 1/x+3 - 2/3-x = 4/x^2-9
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
As in 1 OVER x+3 and 2 OVER 3-x
anonymous
  • anonymous
is it 4/(x^2-9)
anonymous
  • anonymous
yes

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anonymous
  • anonymous
okay then x = 1/3
anonymous
  • anonymous
How'd you do that? o_o
anonymous
  • anonymous
well first thing you want to do is try and get a common factor in the denominator
anonymous
  • anonymous
so what we do is subtract 4/(x^2-9) to the left side
anonymous
  • anonymous
Ohh! I forgot about that part
anonymous
  • anonymous
so we now have: \[1/(x+3) - 2/(-x+3) - 4/(x^2-9)\] So we multiply the first term by (x+3)/(x+3) and the second term by (-x+3)/(-x+3) This gives us \[[(x+3)+(2x-6)-4] / (x^2-9) = 0\]
anonymous
  • anonymous
then simplifies down to (3x-1)/ (x^2-9) = 0 Multiply both sides by (x^2-9) so your left with 3x-1=0 and solve for x so x = 1/3
anonymous
  • anonymous
Long but I hope it helped
anonymous
  • anonymous
thank you again. I'd bake you cookies if I could.
anonymous
  • anonymous
haha thanks i appreciate it and do love cookies lol

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