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anonymous
 5 years ago
Solve the inequality
x 15
 +  <= 4
4 x+7
for domain
anonymous
 5 years ago
Solve the inequality x 15  +  <= 4 4 x+7 for domain

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Multiply both sides by 4(x+7)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I did but that led me to x^29x+172 and that doesnt seem right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[x(x+7) + 4(15) \le 4*4(x+7)\] \[\implies x^2 + 7x + 60 \le 16x + 112\] \[\implies x^2 9x  52 \le 0\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So solve the quadratic for 0 and you have your solutions.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I got 9 and 13......how do I use those to find the domain?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its an inequality theres a different way to solve for the domain

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[(x 13)(x+4) \le 0\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That means that one of those two factors must be negative (but not both) for the relation to hold.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So what values of x will yield a negative in one of either (x13) or (x+4) but not both.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0between 4 and 13? my options for an answer are A. (7,4] U [13, inf) B. (inf,7)U(4,13) C. (inf,7]U[4,13) D. (inf,7)U[4,13] E. (7,4)U(13,inf)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If x is between 4 and 13 (say maybe x=0) we have one positive and one negative, so that seems reasonable.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0We did get rid of a factor of x+7 though when we solved it, so I think your answer is probably D.
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