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anonymous

  • 5 years ago

if 7^(x-1)=6^x what is x?

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  1. anonymous
    • 5 years ago
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    Gonna need a log or an ln to solve this one.

  2. anonymous
    • 5 years ago
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    yeah, but how?

  3. anonymous
    • 5 years ago
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    when i do x-1 log 7 = x log 6 and divide by log 7, the x just cancels out. and im supposed to solve for x..

  4. anonymous
    • 5 years ago
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    Brush up a little operation of logs. Bring one one side then you have log a - lob b = log a/b

  5. anonymous
    • 5 years ago
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    Don't lose your parens too.

  6. anonymous
    • 5 years ago
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    \[(x-1)log 7 = x log 6\] Distribute that log 7 to each term, bring all the terms with x to one side of the equation, etc. etc.

  7. anonymous
    • 5 years ago
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    thansk! =D that makes sense!

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