anonymous
  • anonymous
evaluate limit as x goes to 2 = sin(x-2)/(x^2-4)
Mathematics
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
infinity
anonymous
  • anonymous
take the limit of top and bottom sin(0) = 1 (2^2 - 4) aproaches 0 BUT can never go to zero because you cant divide by zero
anonymous
  • anonymous
so as the denominator goes to 0.00000001 or 0.000000000000000001

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
its ilike this 1/4 then 1/2 then 1/1 then 1/0.000001 then 1/0.0000000000001
anonymous
  • anonymous
This one can be handled with a little manipulation. The bottom can be expanded to (x-2)(x+2). The lim of [sin (x-2)]/(x-2)]=1. That leaves 1/(x+2). So lim is 1/4.
anonymous
  • anonymous
no the bottom cannot be expanded like that
anonymous
  • anonymous
I am guessing by the way these questions are set up that x^2-4 is not sin of, but just a number.
anonymous
  • anonymous
I think the its sin of x-2 so sin(x-2)
anonymous
  • anonymous
divided by x^2 - 4
anonymous
  • anonymous
In that case we are saying the same thing. \[x ^{2}-4=(x-2)(x+2)\]The difference of two squares.
anonymous
  • anonymous
no thats what you are saying
anonymous
  • anonymous
that is impossible to do
anonymous
  • anonymous
I have had a couple beers. But are you telling me that the above is not the difference of two squares?
anonymous
  • anonymous
no it is
anonymous
  • anonymous
maybe your right im sorry
anonymous
  • anonymous
limit as x goes to 2 = sin(x-2)/(x^2-4) 0/0 so Use L'Hopital's rule lim x->2 Cos(x-2)/(2x) = Cos (0) / (2*2) = 1/4

Looking for something else?

Not the answer you are looking for? Search for more explanations.