anonymous
  • anonymous
I need help with exponential regression...I have E(x)=164.96(1.03)^x for equation for high school graduates...need to find the first year of the decade in which number of graduates will reach 5 million
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
E a function of x, E is what and x is what? im guessing E is graduates and x is year?
anonymous
  • anonymous
yes I used cal to get a b and r
anonymous
  • anonymous
plug 5mill into E(x) and solve for x

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anonymous
  • anonymous
yes got that but do I ln or log...can't remember
anonymous
  • anonymous
years are in decades and graduates are in 1000s so would I divide 5 mil by 100
anonymous
  • anonymous
do log base 1.03 there is probably a key on your calculator
anonymous
  • anonymous
is that ln
anonymous
  • anonymous
actually im sorry you are right take the natural log of both sides. and the exponent of x will come out as a multiple of ln(1.03) so \[\ln(1.03^x) = xln(1.03)\] ln(1.03) is just a constant so you can divide by it on both sides
anonymous
  • anonymous
thank you for the confirmation
anonymous
  • anonymous
yeahp
anonymous
  • anonymous
one more thing I have year 2050 from the linear function and year 2070 from the exponential...which one seems more reasonable?
anonymous
  • anonymous
based on the values of correlation factor r the linear function would be but if you're looking at 5 million wouldn't it take less years to get there Exponentially versus linearly
anonymous
  • anonymous
im not sure from what was given i only know of E(x) and x,
anonymous
  • anonymous
L(x)=33.79x-135.77
anonymous
  • anonymous
used 5000 instead of 5 mil bc grads in 1000s is that right?
anonymous
  • anonymous
yeah
anonymous
  • anonymous
yeah to which question, lol?
anonymous
  • anonymous
lol just agreeing with the thing you said about linear versus exponential growth it would have to be 2050. but i would look into that more as to how to get to that answer
anonymous
  • anonymous
ok thanks!

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