anonymous
  • anonymous
How can I solve using elimination and back substitution?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
can some of u just help me with my stereo one
anonymous
  • anonymous
{4x-2y-4z=32 x-y+4z=-13 6x-4y+2z=14}
anonymous
  • anonymous
I already know the first step is 4x-2y-4z=32 x-y-4z=-13

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
5x-4y=19
anonymous
  • anonymous
I become lost after this step
anonymous
  • anonymous
Hello? Are u able youassist?
anonymous
  • anonymous
solve one equation for some variable, then plug in into one of the other equations, then solve for one of the two variables. You then have one of your variable. Though I think it is easier to use Gaussian elimination.
anonymous
  • anonymous
Gaussian elimination? Can you show me how that works?
anonymous
  • anonymous
write the coefficients of each variable for each equation into a matrix like pattern and add or subtract rows from one another until you have the pattern: 100=a 010=b 001=c or 001=a 010=b 100=c
anonymous
  • anonymous
Not really seeing how that will help me get the correct answer
anonymous
  • anonymous
Its better because there is no substituting. You add and subtract rows until you end up with diagonal ones. If the one in the 'a' equation is in the x column, that is your x and so on.
anonymous
  • anonymous
I can help you. When you substitute, you first want to solve for a single variable. So take your equation 4x-2y-4z=32. You can solve for x by adding 2y and 4z to the other side. It is then 4x=2y+4z+32. Then divide by 4 making it x=1/2y+z+8
anonymous
  • anonymous
Now, you can plug that x into another equation. x-y-4z=-13 for instance. When you plug in what you've found for x, you'll only end up with z and y values in it. So (1/2y+z+8)-y-4z=-13
anonymous
  • anonymous
I just used the parentheses to show what the equation was for x. Is this making sense?

Looking for something else?

Not the answer you are looking for? Search for more explanations.