A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
How can I solve using elimination and back substitution?
anonymous
 5 years ago
How can I solve using elimination and back substitution?

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can some of u just help me with my stereo one

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0{4x2y4z=32 xy+4z=13 6x4y+2z=14}

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I already know the first step is 4x2y4z=32 xy4z=13

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I become lost after this step

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hello? Are u able youassist?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0solve one equation for some variable, then plug in into one of the other equations, then solve for one of the two variables. You then have one of your variable. Though I think it is easier to use Gaussian elimination.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Gaussian elimination? Can you show me how that works?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0write the coefficients of each variable for each equation into a matrix like pattern and add or subtract rows from one another until you have the pattern: 100=a 010=b 001=c or 001=a 010=b 100=c

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Not really seeing how that will help me get the correct answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Its better because there is no substituting. You add and subtract rows until you end up with diagonal ones. If the one in the 'a' equation is in the x column, that is your x and so on.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I can help you. When you substitute, you first want to solve for a single variable. So take your equation 4x2y4z=32. You can solve for x by adding 2y and 4z to the other side. It is then 4x=2y+4z+32. Then divide by 4 making it x=1/2y+z+8

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now, you can plug that x into another equation. xy4z=13 for instance. When you plug in what you've found for x, you'll only end up with z and y values in it. So (1/2y+z+8)y4z=13

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I just used the parentheses to show what the equation was for x. Is this making sense?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.