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anonymous
 5 years ago
what would be integration of ∫e^(x+y+z)dx
and ∫∫∫e^(x+y+z)dx dy dz ??
anonymous
 5 years ago
what would be integration of ∫e^(x+y+z)dx and ∫∫∫e^(x+y+z)dx dy dz ??

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well, you can split that up into e^x+e^y+e^z if that helps to get you started.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ya we can split it but it won't create complex problem in solving multiple integration....???

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No, it makes it much easier. Because then you have ʃʃ e^y*e^z ʃe^x dx dy dz.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do you have no bounds on that triple integral?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i mean yes it has no bounds....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It's just gonna end up being e^(x+y+z) in the end after all of the integrating then.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do you understand why?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0because integration of e^x is same.... i guess

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well, the integral of e^x is just e^x. Then after that you'd end up with ʃʃe^x*e^y*e^z dy dz. You'd then change it to ʃe^x*e^zʃe^y dy dz. The integral of e^y is e^y again. You'd repeat the same thing with e^z.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh ya...... thanks a lot.... i think i got it...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No problem, glad that helped.
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